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Introducing vectors for engineering applications
Introducing vectors for engineering applications

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2.3 Converting between vector forms

It is useful to be able to convert between the different forms of vectors, so that we can make use of the form that is most appropriate for a given situation. For example, the vector in Figure 18(a) represents the displacement of London from Milton Keynes, and direction and angle are the most intuitive description for this vector. London is approximately 65 km south-east of Milton Keynes. Similarly, the vector in Figure 18(b) represents the motion of an aircraft, and for describing the ground speed of the aircraft, a description of the vector in terms of horizontal and vertical components is required.

Described image
Figure 18 Examples of vectors: (a) displacement of London from Milton Keynes; (b) motion of an aircraft

In both situations it is useful to be able to convert between vector forms. For example, it may be necessary to describe how far east London is from Milton Keynes, and how far south. To describe the direction in which the aircraft is flying, it is useful to use the resultant velocity.

The mathematics that allows us to convert between different forms of vectors.

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Figure 19 A vector and its components

We have already identified how to calculate the magnitude of the component vectors of a vector. For example, the vector bold v in Figure 19 has magnitude absolute value of v and direction theta , and its components are defined as vertical equals absolute value of v times sine of theta of i and horizontal equals absolute value of v times cosine of theta of j .

Putting these into component form we have the following result.

Component form of a vector in terms of its magnitude and angle with the positive x-axis

If the vector bold v makes an angle theta with the positive x -axis, then

v equals left parenthesis absolute value of v times cosine of theta right parenthesis times i plus left parenthesis absolute value of v times sine of theta right parenthesis times j full stop

Activity 10

Find the component forms of the following vectors. Give your answers to two decimal places.

  • a.Vector bold a with magnitude 78 and direction given by an angle of 216° with the positive x -axis.

  • b.vector bold w with magnitude 4.4 and direction given by an angle of pi divided by five radians with the positive x -axis.

Described image
Figure 20 A vector v equals a times i plus b times j

Going the other way, to find the magnitude and direction of a vector from its component form, the reasoning is the same as how to convert between Cartesian and polar coordinates. For example, the vector bold v illustrated in Figure 20 has horizontal component of magnitude a and vertical component of magnitude b , and in component form is given by v equals a times i plus b times j . To calculate the magnitude of bold v , we can use Pythagoras’ theorem, and to calculate the angle theta , we can use the inverse tangent function.

Magnitude and direction of a vector in terms of its components

If the vector bold v has the component form v equals a times i plus b times j , then its magnitude is given by

absolute value of v equals Square root of a squared plus b squared

and its direction is given by the angle theta measured anticlockwise from the positive x -axis, where

theta equals tangent super negative one of b divided by a full stop

Remember, when using the inverse tan function, care must be taken to ensure that the answer given by a calculator is correct.

Activity 11

Find the magnitude to two decimal places and direction to one decimal place of the following vectors.

  • a. negative three times i plus j

  • b. vector element 1 negative two element 2 zero

  • c. vector element 1 two element 2 four