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Introducing vectors for engineering applications
Introducing vectors for engineering applications

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4.2 Scalar product of a vector from magnitude and direction

Another way to consider the scalar product is to consider how it is defined in terms of the magnitudes and directions of two vectors. Consider again the vectors bold a and bold b in Figure 29. We want to find out how much vector bold b will grow vector bold a. So again we want to identify how much the vectors interact – and one way to do this is to determine how much vector bold a points in the direction of vector bold b.

Described image
Figure 31 Finding the scalar product of bold a and bold b by comparing magnitudes and directions

In Figure 31, the vectors are arranged so that their tails meet, and this makes it possible to compare their magnitudes and directions. To make this explicit, we can draw the components of bold a, not in terms of horizontal and vertical directions, but in terms of the direction where bold b is pointing, as illustrated in Figure 32(a). Formally, the component of bold a that points in the direction of bold b is called the projection of bold a onto bold b, and if the angle between bold a and bold b is theta, then the length of the projection of bold a onto bold b is absolute value of a times cosine of theta, as shown in Figure 32(b).

Described image
Figure 32 Projecting bold a onto bold b

Comparing the components of bold a with bold b will give us a measure of how much bold a and bold b interact, as illustrated in Figure 33. In the direction of bold b, bold a has a component of magnitude absolute value of a times cosine of theta, and bold b has a component of magnitude absolute value of b, so the contribution to the value of a dot operator b is absolute value of a times cosine of theta dot operator absolute value of b. Perpendicular to bold b, bold a has a component of magnitude absolute value of a times sine of theta, and bold b has a component of magnitude 0, so the contribution to the value of a dot operator b is 0.

Described image
Figure 33 Interacting component vectors in the scalar product of bold a and bold b

So

a dot operator b equals absolute value of a times cosine of theta dot operator absolute value of b comma

and this is a measure of how much the scalar quantity absolute value of b grows the scalar quantity absolute value of a times cosine of theta.

absolute value of a times cosine of theta and absolute value of bold b are parallel, so

absolute value of a times cosine of theta dot operator absolute value of b equals absolute value of a times cosine of theta multiplication absolute value of b or absolute value of a times absolute value of b times cosine of theta comma

and the scalar product is given by

a dot operator b equals absolute value of a times absolute value of b times cosine of theta full stop

Scalar product of vectors in terms of magnitude and direction

The scalar product of two vectors bold a and bold b is

a dot operator b equals absolute value of a times absolute value of b times cosine of theta comma

where theta is the angle between bold a and bold b.

Activity 20

Suppose that bold u, bold v and bold w are vectors with magnitudes 4, 3 and 2 respectively, and directions as shown in the following figure.

Find the following scalar products.

  • a.u dot operator v

  • b.u dot operator w

  • c.u dot operator u