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Introducing vectors for engineering applications
Introducing vectors for engineering applications

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4.3 Properties of the scalar product

Activity 20 illustrates two important properties of the scalar product. First, if two non-zero vectors are perpendicular, then their scalar product is zero. This is because if bold a and bold b are perpendicular, then

equation sequence part 1 a dot operator b equals part 2 absolute value of a times absolute value of b times cosine of 90 super ring operator equals part 3 absolute value of a times absolute value of b multiplication zero equals part 4 zero full stop

This also works the other way, so that if the scalar product of two non-zero vectors is zero, then the vectors are perpendicular. This is because if bold a and bold b are non-zero vectors, then the only way that a dot operator b can be equal to zero is if cosine of theta equals zero . This implies that theta equals 90 super ring operator .

The second property is that the scalar product of a vector with itself is equal to the square of the magnitude of the vector. This is because if bold a is any non-zero vector, then the angle between bold a and itself is 0°, so

equation sequence part 1 a dot operator a equals part 2 absolute value of a times absolute value of a times cosine of zero super ring operator equals part 3 absolute value of a times absolute value of a multiplication one equals part 4 absolute value of a squared full stop

These, and other, properties of the scalar product in the following list can all be proved using the definition of the scalar product in a similar way.

Scalar product properties

The following properties hold for all vectors bold a , bold b and bold c , and every scalar m .

  1. If bold a and bold b are non-zero and perpendicular, then a dot operator b equals zero and b dot operator a equals zero .

  2. a dot operator a equals absolute value of a squared

  3. a dot operator b equals b dot operator a

  4. a postfix dot operator times left parenthesis b plus c right parenthesis equals a dot operator b plus a dot operator c

  5. equation sequence part 1 left parenthesis m times a right parenthesis times prefix dot operator of b equals part 2 m times left parenthesis a dot operator b right parenthesis equals part 3 a postfix dot operator times left parenthesis m times b right parenthesis

We can use these properties to simplify expressions containing scalar products of vectors.

Example 7 Simplifying an expression containing a scalar product

Expand and simplify the expression left parenthesis a plus b right parenthesis dot operator left parenthesis a plus b right parenthesis , where bold a and bold b are vectors.

Solution

Expand the brackets by using property 4:

equation sequence part 1 left parenthesis a plus b right parenthesis dot operator left parenthesis a plus b right parenthesis equals part 2 a postfix dot operator times left parenthesis a plus b right parenthesis plus b postfix dot operator times left parenthesis a plus b right parenthesis equals part 3 sum with 4 summands a dot operator a plus a dot operator b plus b dot operator a plus b dot operator b full stop

Simplify by using property 3, so:

left parenthesis a plus b right parenthesis dot operator left parenthesis a plus b right parenthesis equals sum with 3 summands a dot operator a plus two times a dot operator b plus b dot operator b full stop

Using property 2, simplify further to get:

left parenthesis a plus b right parenthesis dot operator left parenthesis a plus b right parenthesis equals sum with 3 summands absolute value of a squared plus two times a dot operator b plus absolute value of b squared full stop

Activity 21

Expand and simplify the expression left parenthesis a plus b right parenthesis dot operator left parenthesis a minus b right parenthesis , where bold a and bold b are vectors.