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<Item xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" Rendering="OpenLearn" SchemaVersion="2.0" Template="Generic_A4_Unnumbered" TextType="CompleteItem" id="X-MU120_4M4" xsi:noNamespaceSchemaLocation="http://www.open.edu/openlearn/ocw/mod/oucontent/schemas/v2_0/OUIntermediateSchema.xsd" x_oucontentversion="2025011400"><meta name="vle:server" content="http://www.open.edu/openlearn/ocw"/><meta name="vle:osep" content="false"/><meta name="equations" content="mathjax"/><meta name="dc:source" content="http://www.open.edu/openlearn/science-maths-technology/mathematics-and-statistics/mathematics-education/squares-roots-and-powers/content-section-0?utm_source=openlearn&amp;utm_campaign=ol&amp;utm_medium=ebook"/><CourseCode>MU120_4M4</CourseCode><CourseTitle>Open mathematics</CourseTitle><ItemID/><ItemTitle>Squares, roots and powers</ItemTitle><FrontMatter><Imprint><Standard><GeneralInfo><Paragraph><b>About this free course</b></Paragraph><Paragraph>This free course provides a sample of level 1 study in Mathematics: <a href="http://www.open.ac.uk/courses/find/mathematics?utm_source=openlearn&amp;utm_campaign=ol&amp;utm_medium=ebook">www.open.ac.uk/courses/find/mathematics</a>.</Paragraph><Paragraph>This version of the content may include video, images and interactive content that may not be optimised for your device. </Paragraph><Paragraph>You can experience this free course as it was originally designed on OpenLearn, the home of free learning from The Open University: <a href="http://www.open.edu/openlearn/science-maths-technology/mathematics-and-statistics/mathematics-education/squares-roots-and-powers/content-section-0?utm_source=openlearn&amp;utm_campaign=ol&amp;utm_medium=ebook">www.open.edu/openlearn/science-maths-technology/mathematics-and-statistics/mathematics-education/squares-roots-and-powers/content-section-0</a>.</Paragraph><Paragraph>There you’ll also be able to track your progress via your activity record, which you can use to demonstrate your learning.</Paragraph></GeneralInfo><Address><AddressLine>The Open University, Walton Hall, Milton Keynes, MK7 6AA</AddressLine></Address><FirstPublished><Paragraph/></FirstPublished><Copyright><Paragraph>Copyright © 2016 The Open University</Paragraph></Copyright><Rights><Paragraph/><Paragraph>
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                <Covers><Cover template="false" type="ebook" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/Squares_roots_and_powers_ebook_cover.jpg"/><Cover template="false" type="A4" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/Squares_roots_and_powers_ebook_cover.jpg"/></Covers></FrontMatter><Unit><UnitID/><UnitTitle/>


<Session><Title>Introduction</Title><Paragraph>This free course, <i>Squares, roots and powers</i>, reminds you about powers of numbers, such as squares and square roots. In particular, powers of 10 are used to express large and small numbers in a convenient form, known as <i>scientific notation</i>, which is used by scientific calculators.</Paragraph><Paragraph> </Paragraph><Paragraph>This OpenLearn course provides a sample of level 1 study in <a href="http://www.open.ac.uk/courses/find/mathematics?utm_source=openlearn&amp;utm_campaign=ol&amp;utm_medium=ebook">Mathematics</a>.</Paragraph>
            </Session>

                <Session>
                    <Title>Learning outcomes</Title>
                    <Paragraph>After studying this course, you should be able to:</Paragraph>
                    <UnNumberedList>
                        <ListItem>evaluate the squares, cubes and other powers of positive and negative numbers with or without your calculator</ListItem>
                        <ListItem>estimate square roots and calculate them using your calculator</ListItem>
                        <ListItem>describe the power notation for expressing numbers</ListItem>
                        <ListItem>use your calculator to find powers of numbers</ListItem>
                        <ListItem>multiply and divide powers of the same number.</ListItem>
                        </UnNumberedList>
                    </Session>

                <Session id="ses001"><Title>1 Squares, cubes and roots</Title>
                <Section id="sec001_001"><Title>1.1 Squares</Title><Paragraph>In general, to <b>square</b> a number, multiply it by itself. This is denoted by writing a small ‘2’ to the top right of the number,</Paragraph><Paragraph>e.g. 4 squared, written 4<sup>2</sup>, is 4 × 4 = 16.</Paragraph><Figure id="figi058"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i058i.jpg" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i058i.jpg" x_folderhash="eb44170e" x_contenthash="8448132b" x_imagesrc="mu120_a_i058i.jpg" x_imagewidth="190" x_imageheight="192"/></Figure><Example id="exa001"><Heading>Example 1</Heading><Paragraph>A gardener is planning to create a square patio using square concrete slabs. A row of 11 large slabs just fits across the width of the areas she wants to cover.</Paragraph><Figure id="figi057"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i057i.jpg" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i057i.jpg" x_folderhash="eb44170e" x_contenthash="1d709e67" x_imagesrc="mu120_a_i057i.jpg" x_imagewidth="426" x_imageheight="364"/></Figure><UnNumberedList><ListItem><Paragraph>(a) How many rows of slabs will she use?</Paragraph></ListItem><ListItem><Paragraph>(b) How many slabs will she need altogether?</Paragraph></ListItem><ListItem><Paragraph>(c) The slabs are 0.75 m square. What area will the patio be?</Paragraph></ListItem></UnNumberedList><Answer><!--<SubHeading>Solution</SubHeading>-->
                <Paragraph/><UnNumberedList><ListItem><Paragraph>(a) Since the patio is square and it is 11 slabs wide, it must be 11 slabs long too, so there are 11 rows of slabs.</Paragraph></ListItem><ListItem><Paragraph>(b) That means that altogether she will need 11 × 11, or 11<sup>2</sup> = 121 slabs.</Paragraph></ListItem><ListItem><Paragraph>(c) There are several ways of finding the area of the patio. One method is to say that each slab is 0.75 m by 0.75 m, which is an area of 0.75<sup>2</sup> square metres. So the patio is 11<sup>2</sup> × 0.75<sup>2</sup> square metres. Using a calculator gives 68.0625 square metres. An alternative method is to say that each side of the patio is 11 × 0.75 m. so the area of the patio is (11 × 0.75)<sup>2</sup> square metres. Using a calculator again gives 68.0625 square metres. (Notice (11 × 0.75)<sup>2</sup> = 11<sup>2</sup> × 0.75<sup>2</sup>.) </Paragraph></ListItem><ListItem><Paragraph>So the patio will be just over 68 square metres.</Paragraph></ListItem></UnNumberedList></Answer></Example><Example id="exa002"><Heading>Example 2</Heading><Paragraph>In an art course the teacher plans to asks each of the pupils to draw a sketch of every child in the class, including a self-portrait, on separate sheets of paper. There are 26 children in the class. Find an upper estimate for the number of sheets of drawing paper he should supply for the whole class. Find a lower estimate. Use your calculator to find the exact number of sheets of paper.</Paragraph><Answer><!--<SubHeading>Solution</SubHeading>--><Paragraph>Each of the 26 children will need 26 pieces of paper, so altogether 26 × 26, i.e. 26<sup>2</sup> sheets of paper are required.</Paragraph><Paragraph>Upper estimate: If there were 30 pupils in the class he would need 30 × 30 = 900 sheets of paper.</Paragraph><Paragraph>Lower estimate: If there were only 20 pupils the teacher would need 20<sup>2</sup> = 400 sheets of paper.</Paragraph><Paragraph>So he will need something in between 400 and 900.</Paragraph><Paragraph>On the calculator, 26<sup>2</sup> = 676.</Paragraph><Paragraph>This is in reasonable agreement with the rough check, so 676 sheets of paper are required. (He would probably take 700 to have spares.)</Paragraph></Answer></Example><SubSection id="sec001_001_001"><Title>1.1.1 Try some yourself</Title><Activity id="act001"><Heading>Activity 1</Heading><Question><Paragraph>Evaluate the following:</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 6<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 0.5<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 1.5<sup>2</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 6<sup>2 </sup> = 6 × 6 = 36</Paragraph></ListItem><ListItem><Paragraph>(b) 0.5<sup>2</sup> = 0.5 × 0.5 = 0.25</Paragraph></ListItem><ListItem><Paragraph>(c) 1.5<sup>2</sup> = 1.5 × 1.5 = 2.25</Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act002"><Heading>Activity 2</Heading><Question><Paragraph> Square carpet tiles measure 50 cm by 50 cm (or 0.5 m by 0.5 m).</Paragraph><UnNumberedList><ListItem><Paragraph>(a) What area is covered by one tile? Give your answer (i) in square centimetres (cm<sup>2</sup>) and (ii) in square metres (m<sup>2</sup>).</Paragraph></ListItem><ListItem><Paragraph>(b) What area, in m<sup>2</sup>, will 100 tiles cover?</Paragraph></ListItem><ListItem><Paragraph>(c) How many tiles are needed to cover 1 square metre?</Paragraph></ListItem><ListItem><Paragraph>(d) How many tiles are needed to cover a room with an area of 16 m<sup>2</sup>?</Paragraph></ListItem><ListItem><Paragraph>(e) If the room in (d) is square, how many tiles go along each edge?</Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a)(i) One tile covers 50 × 50 = 2500 cm<sup>2</sup>.</Paragraph></ListItem><ListItem><Paragraph>(a)(ii) To convert this to m<sup>2</sup>, you could divide by 100<sup>2</sup> to give <InlineFigure><Image height="" movedownby="8" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i282e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i282e.gif" x_folderhash="eb44170e" x_contenthash="dad27c6c" x_imagesrc="mu120_a_i282e.gif" x_imagewidth="86" x_imageheight="30"/></InlineFigure> = 0.25 m<sup>2</sup>.</Paragraph></ListItem><ListItem><Paragraph>Alternatively (and more simply) convert first: each tile measures</Paragraph></ListItem><ListItem><Paragraph> 0.5 m × 0.5 m and so has an area 0.5 m × 0.5 m = 0.25 m<sup>2</sup>.</Paragraph></ListItem><ListItem><Paragraph>(b) One tile covers 0.25 m<sup>2</sup> so 100 tiles cover 100 × 0.25 = 25 m<sup>2</sup>.</Paragraph></ListItem><ListItem><Paragraph>(c) Since each tile covers 0.25 m<sup>2</sup>, 4 tiles will cover 4 × 0.25 = 1 m<sup>2</sup>.</Paragraph></ListItem><ListItem><Paragraph>(d) 4 tiles cover 1 m<sup>2</sup> so 16 × 4 = 64 tiles cover 16 m<sup>2</sup>.</Paragraph></ListItem><ListItem><Paragraph>(e) If the room is square and the area is 16 m<sup>2</sup> then each edge must be 4 m, since 4 × 4 = 16 (or <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i283e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i283e.gif" x_folderhash="eb44170e" x_contenthash="19e04b18" x_imagesrc="mu120_a_i283e.gif" x_imagewidth="24" x_imageheight="15"/></InlineFigure>=4). So 8 tiles go along each edge. </Paragraph></ListItem><ListItem><Paragraph>(You could also have deduced this from your answer to (d), since 64 tiles is 8 × 8 tiles.)</Paragraph></ListItem></UnNumberedList></Answer></Activity></SubSection></Section><Section id="sec001_002"><Title>1.2 Squaring fractions and negative numbers</Title><Paragraph>You have now seen how to find squares of whole numbers and decimals. What about fractions? The rule is as before: to square a fraction, just multiply it by itself.</Paragraph><Paragraph>For example:</Paragraph><Equation id="ueqn034"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u034e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u034e.gif" x_folderhash="eb44170e" x_contenthash="140bc8f1" x_imagesrc="mu120_a_u034e.gif" x_imagewidth="120" x_imageheight="39"/></Equation><Paragraph>In Example 1, you could have used <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i288e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i288e.gif" x_folderhash="eb44170e" x_contenthash="ac422cfa" x_imagesrc="mu120_a_i288e.gif" x_imagewidth="7" x_imageheight="27"/></InlineFigure> instead of 0.75. Check on your calculator that 0.75<sup>2</sup> = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i289e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i289e.gif" x_folderhash="eb44170e" x_contenthash="82f4211b" x_imagesrc="mu120_a_i289e.gif" x_imagewidth="14" x_imageheight="27"/></InlineFigure>. Both answers should be 0.5625.</Paragraph><Paragraph>There may be contexts where you need to square negative numbers. Take care when doing so. Use the brackets if in doubt. Calculating by hand gives, for example:</Paragraph><Quote id="eqtn_002"><Paragraph>(<sup>−</sup>9)<sup>2</sup> = <sup>−</sup>9 × <sup>−</sup>9 = 81</Paragraph></Quote><Paragraph>However, keying in <sup>−</sup>9 and then squaring will give <sup>−</sup>81 on many scientific and graphics calculators. Why? They calculate exactly what you have asked for, i.e. <sup>−</sup>9<sup>2</sup>. Since 9<sup>2</sup> is 81, <sup>−</sup>9<sup>2</sup> is <sup>−</sup>81. The number 9 is squared <i>first</i>, to give 81, and <i>then</i> made negative, to give <sup>−</sup>81. Brackets are needed to tell the calculator to make the 9 negative and <i>then</i> square:</Paragraph><Quote id="eqtn_003"><Paragraph>(<sup>−</sup>9)<sup>2</sup> = 81,</Paragraph></Quote><Paragraph>but without brackets <sup>−</sup>9<sup>2</sup> often means <sup>−</sup>(9<sup>2</sup>).</Paragraph><Paragraph>To avoid any ambiguity, it is <i>always</i> best to use brackets when squaring negative numbers.</Paragraph><SubSection id="sec001_002_001"><Title>1.2.1 Try some yourself</Title><Activity id="act003"><Heading>Activity 3</Heading><Question><Paragraph>Without using your calculator, find the following:</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 10<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 100<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 0.1<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(d) 0.01<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(e) <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i290e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i290e.gif" x_folderhash="eb44170e" x_contenthash="f5129bd3" x_imagesrc="mu120_a_i290e.gif" x_imagewidth="27" x_imageheight="41"/></InlineFigure></Paragraph></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(f) (<sup>−</sup>3)<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(g) (<sup>−</sup>1)<sup>2</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 10<sup>2</sup> = 10 × 10 = 100</Paragraph></ListItem><ListItem><Paragraph>(b) 100<sup>2</sup> = 100 × 100 = 10 000</Paragraph></ListItem><ListItem><Paragraph>(c) 0.1<sup>2</sup> = 0.1 × 0.1 = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si124e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si124e.gif" x_folderhash="eb44170e" x_contenthash="7acb5c69" x_imagesrc="mu120_a_si124e.gif" x_imagewidth="82" x_imageheight="27"/></InlineFigure> = 0.01</Paragraph></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(d) 0.01<sup>2</sup> = 0.01 × 0.01 = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si125e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si125e.gif" x_folderhash="eb44170e" x_contenthash="6c811ec0" x_imagesrc="mu120_a_si125e.gif" x_imagewidth="114" x_imageheight="27"/></InlineFigure></Paragraph><Paragraph>  = 0.0001</Paragraph></ListItem><ListItem><Paragraph>(e) <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si126e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si126e.gif" x_folderhash="eb44170e" x_contenthash="58c2b37d" x_imagesrc="mu120_a_si126e.gif" x_imagewidth="101" x_imageheight="41"/></InlineFigure></Paragraph></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(f) (<sup>−</sup>3)<sup>2</sup> = <sup>−</sup>3 × <sup>−</sup>3 = 9</Paragraph></ListItem><ListItem><Paragraph>(g) (<sup>−</sup>1)<sup>2</sup> = <sup>−</sup>1 × <sup>−</sup>1 = 1</Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act004"><Heading>Activity 4</Heading><Question><Paragraph>Explain why brackets should be used when writing the expression (<sup>−</sup>1)<sup>2</sup>.</Paragraph></Question><Answer><Paragraph>If you write <sup>−</sup>1<sup>2</sup> it is not clear whether you mean to square 1 first then make the answer negative, giving <sup>−</sup>1, or to square <sup>−</sup>1, giving 1. Many calculators would assume you meant <sup>−</sup>(1)<sup>2</sup>, and return the answer <sup>−</sup>1.</Paragraph></Answer></Activity><Activity id="act005"><Heading>Activity 5</Heading><Question><Paragraph>Use your calculator to find the following, using your answers to the appropriate parts of <CrossRef idref="act003">Question 1</CrossRef> as estimates.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 96<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 10.65<sup>2</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) Rough check: 100<sup>2</sup> = 10 000.</Paragraph><Paragraph>Calculator gives 96<sup>2</sup> = 9216.</Paragraph></ListItem><ListItem><Paragraph>(b) Rough check: 10<sup>2</sup> = 100.</Paragraph><Paragraph>Calculator gives 10.65<sup>2</sup> = 113.4225.</Paragraph></ListItem></UnNumberedList></Answer></Activity></SubSection></Section><Section id="sec001_003"><Title>1.3 Square roots</Title><Paragraph>Given any number, you now know how to find its square. But, given the squared number, how do you find the original number?</Paragraph><Example id="exa003"><Heading>Example 3</Heading><Paragraph>If the gardener in <CrossRef idref="exa001">Example 1</CrossRef> had only 49 paving slabs, what size of square patio could she make?</Paragraph><Answer><!--<SubHeading>Solution</SubHeading>--><Paragraph>You probably spotted that 49 is 7 × 7, or 7<sup>2</sup>, so she could make a square patio 7 slabs by 7 slabs.</Paragraph></Answer></Example><Paragraph>Since 7<sup>2</sup> = 49, 7 is the square root of 49, written</Paragraph><Quote id="eqtn_004"><Paragraph>7 = <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u037e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u037e.gif" x_folderhash="eb44170e" x_contenthash="82f6f1e8" x_imagesrc="mu120_a_u037e.gif" x_imagewidth="26" x_imageheight="15"/></InlineFigure>.</Paragraph></Quote><Paragraph>Sometimes you can just look at a number and spot its square root, if the number is a ‘perfect square’ (i.e. the result of squaring a whole number). For example, 25 is a perfect square, and <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i291e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i291e.gif" x_folderhash="eb44170e" x_contenthash="62e37c8e" x_imagesrc="mu120_a_i291e.gif" x_imagewidth="24" x_imageheight="15"/></InlineFigure> = 5. But more often than not you will need to use your calculator for square roots, and it is important to be able to find rough estimates as a check on your calculator work. So if you wanted <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i292e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i292e.gif" x_folderhash="eb44170e" x_contenthash="9e21b34f" x_imagesrc="mu120_a_i292e.gif" x_imagewidth="24" x_imageheight="15"/></InlineFigure>, you would know that it would lie between <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u037e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u037e.gif" x_folderhash="eb44170e" x_contenthash="82f6f1e8" x_imagesrc="mu120_a_u037e.gif" x_imagewidth="26" x_imageheight="15"/></InlineFigure> = 7 and <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i294e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i294e.gif" x_folderhash="eb44170e" x_contenthash="57c45eb8" x_imagesrc="mu120_a_i294e.gif" x_imagewidth="25" x_imageheight="15"/></InlineFigure> = 8, and you would expect an answer of seven point something. (It is 7.416 …).</Paragraph><Paragraph>Technically, <sup>−</sup>7 is also a square root of 49, since (<sup>−</sup>7)<sup>2</sup> = 49. This is called the negative square root. The sign √ is customarily used to denote the positive square root, so <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u037e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u037e.gif" x_folderhash="eb44170e" x_contenthash="82f6f1e8" x_imagesrc="mu120_a_u037e.gif" x_imagewidth="26" x_imageheight="15"/></InlineFigure> = 7 and <sup>−</sup><InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u037e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u037e.gif" x_folderhash="eb44170e" x_contenthash="82f6f1e8" x_imagesrc="mu120_a_u037e.gif" x_imagewidth="26" x_imageheight="15"/></InlineFigure> = <sup>−</sup>7.</Paragraph><Paragraph>In <CrossRef idref="exa003">Example 3</CrossRef>, only the positive square root is relevant (patios have positive length sides).</Paragraph><Example id="exa004"><Heading>Example 4</Heading><Paragraph>The owners of a new house, with a bare earth garden, see an advertisement for 44 square metres of turf, ‘free to a good home – only pay transportation’. They were planning a square lawn surrounded by flower beds.</Paragraph><Paragraph>Find a rough estimate for the square root of 44. Use your calculator to find <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i297e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i297e.gif" x_folderhash="eb44170e" x_contenthash="4280fdfc" x_imagesrc="mu120_a_i297e.gif" x_imagewidth="26" x_imageheight="15"/></InlineFigure> and find the size of the square lawn which the turf would make.</Paragraph><Answer><!--<SubHeading>Solution</SubHeading>--><Paragraph>Rounding 44 down to 40 doesn't help – you don't know the square root of 40 either! But you do know that 6<sup>2</sup> = 36 (which is less than 44) and 7<sup>2</sup> = 49 (which is greater than 44) so <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i297e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i297e.gif" x_folderhash="eb44170e" x_contenthash="4280fdfc" x_imagesrc="mu120_a_i297e.gif" x_imagewidth="26" x_imageheight="15"/></InlineFigure> lies between 6 and 7. You could leave the answer as ‘between 6 and 7’ or guess it as 6.5, say. The calculated answer is 6.6332 (rounded to four decimal places). So the turf would make a lawn about 6.6 m square.</Paragraph></Answer></Example><SubSection id="sec001_003_001"><Title>1.3.1 Try some yourself</Title><Activity id="act006"><Heading>Activity 6</Heading><Question><Paragraph>The new home owners from Example 4 above want to price grass seed, as well as the turf (transport only). The best buy seems to be loose seed, which says ‘1 kilo covers 80 m<sup>2</sup>’. They wonder what length the side of an 80 m<sup>2</sup> square lawn would be? Make an estimate and then use your calculator to find <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i299e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i299e.gif" x_folderhash="eb44170e" x_contenthash="253c17d4" x_imagesrc="mu120_a_i299e.gif" x_imagewidth="25" x_imageheight="15"/></InlineFigure> and hence the side of the square lawn.</Paragraph></Question><Answer><Paragraph> A square of side 9 m has an area of 81 m<sup>2</sup>. So 80 m<sup>2</sup> would be a little less than this.</Paragraph><Paragraph><InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i299e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i299e.gif" x_folderhash="eb44170e" x_contenthash="253c17d4" x_imagesrc="mu120_a_i299e.gif" x_imagewidth="25" x_imageheight="15"/></InlineFigure> = 8.94.... So the length of the side of the square lawn would be 8.9 m.</Paragraph></Answer></Activity><Activity id="act007"><Heading>Activity 7</Heading><Question><Paragraph>Use your calculator to find each of the following, estimating the answer first in each case.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i300e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i300e.gif" x_folderhash="eb44170e" x_contenthash="bb83e10c" x_imagesrc="mu120_a_i300e.gif" x_imagewidth="32" x_imageheight="15"/></InlineFigure></Paragraph></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(b) <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i301e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i301e.gif" x_folderhash="eb44170e" x_contenthash="c82e931d" x_imagesrc="mu120_a_i301e.gif" x_imagewidth="38" x_imageheight="15"/></InlineFigure></Paragraph></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(c) <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i302e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i302e.gif" x_folderhash="eb44170e" x_contenthash="ddb26774" x_imagesrc="mu120_a_i302e.gif" x_imagewidth="38" x_imageheight="15"/></InlineFigure></Paragraph></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(d) <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i303e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i303e.gif" x_folderhash="eb44170e" x_contenthash="0a9ad1c2" x_imagesrc="mu120_a_i303e.gif" x_imagewidth="47" x_imageheight="15"/></InlineFigure></Paragraph></ListItem></UnNumberedList><Paragraph>Where necessary, round your answers to four decimal places.</Paragraph></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) Since 12 × 12 = 144, the answer must be <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i300e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i300e.gif" x_folderhash="eb44170e" x_contenthash="bb83e10c" x_imagesrc="mu120_a_i300e.gif" x_imagewidth="32" x_imageheight="15"/></InlineFigure> = 12. The calculator confirms this.</Paragraph></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(b) Since 3<sup>2</sup> = 9 and 4<sup>2</sup> = 16, <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i301e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i301e.gif" x_folderhash="eb44170e" x_contenthash="c82e931d" x_imagesrc="mu120_a_i301e.gif" x_imagewidth="38" x_imageheight="15"/></InlineFigure> must lie between 3 and 4.</Paragraph></ListItem><ListItem><Paragraph>Calculator gives <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i301e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i301e.gif" x_folderhash="eb44170e" x_contenthash="c82e931d" x_imagesrc="mu120_a_i301e.gif" x_imagewidth="38" x_imageheight="15"/></InlineFigure><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 3.7947 rounded to four decimal places.</Paragraph></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(c) Since 1<sup>2</sup> = 1 and 2<sup>2</sup> = 4, <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i302e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i302e.gif" x_folderhash="eb44170e" x_contenthash="ddb26774" x_imagesrc="mu120_a_i302e.gif" x_imagewidth="38" x_imageheight="15"/></InlineFigure> must lie between 1 and 2.</Paragraph><Paragraph>Calculator gives <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i302e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i302e.gif" x_folderhash="eb44170e" x_contenthash="ddb26774" x_imagesrc="mu120_a_i302e.gif" x_imagewidth="38" x_imageheight="15"/></InlineFigure> = 1.2.</Paragraph></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(d) Since 0.3<sup>2</sup> = 0.09 and 0.4<sup>2</sup> = 0.16, <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i303e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i303e.gif" x_folderhash="eb44170e" x_contenthash="0a9ad1c2" x_imagesrc="mu120_a_i303e.gif" x_imagewidth="47" x_imageheight="15"/></InlineFigure> must lie between 0.3 and 0.4.</Paragraph><Paragraph>Looking at the pattern of parts (a) and (c), and since <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i301e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i301e.gif" x_folderhash="eb44170e" x_contenthash="c82e931d" x_imagesrc="mu120_a_i301e.gif" x_imagewidth="38" x_imageheight="15"/></InlineFigure> = 3.7947, a good guess would be that <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i303e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i303e.gif" x_folderhash="eb44170e" x_contenthash="0a9ad1c2" x_imagesrc="mu120_a_i303e.gif" x_imagewidth="47" x_imageheight="15"/></InlineFigure> = 0.3795 rounded to four decimal places.</Paragraph><Paragraph>Indeed, the calculator gives <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i303e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i303e.gif" x_folderhash="eb44170e" x_contenthash="0a9ad1c2" x_imagesrc="mu120_a_i303e.gif" x_imagewidth="47" x_imageheight="15"/></InlineFigure><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 0.3795 rounded to four decimal places.</Paragraph></ListItem></UnNumberedList></Answer></Activity></SubSection></Section><Section id="sec001_004"><Title>1.4 Cubes</Title><Paragraph>To find the cube of a number, multiply three copies of it together. For example:</Paragraph><Equation id="ueqn038"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u038e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u038e.gif" x_folderhash="eb44170e" x_contenthash="7d3e2556" x_imagesrc="mu120_a_u038e.gif" x_imagewidth="231" x_imageheight="41"/></Equation><Paragraph>You can use your calculator to find cubes. 2<sup>3</sup> is ‘two cubed’ or ‘two to the power three’. Just as ‘square root’ is the opposite process to squaring, so 'cube root' is the opposite process to cubing. </Paragraph><Paragraph>4<sup>3</sup> = 64, so <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i304e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i304e.gif" x_folderhash="eb44170e" x_contenthash="fe288963" x_imagesrc="mu120_a_i304e.gif" x_imagewidth="25" x_imageheight="16"/></InlineFigure> = 4.</Paragraph><Paragraph>In the same way that square units are used to measure area, cubic units are used to measure volume. A cube measuring 1 cm × 1 cm × 1 cm has a volume of 1 centimetre cubed, or 1 cubic centimetre, written as 1 cm<sup>3</sup>, or 1 cc. The volume of a ‘box’ is length x width x height, so the volume of this cube (10 mm × 10 mm × 10 mm) in millimetres is</Paragraph><Paragraph>   1 cm<sup>3</sup> = 10 mm × 10 mm × 10 mm = 1000 mm<sup>3</sup>.</Paragraph><Figure id="figi059"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i059i.jpg" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i059i.jpg" x_folderhash="eb44170e" x_contenthash="b5866032" x_imagesrc="mu120_a_i059i.jpg" x_imagewidth="511" x_imageheight="347"/></Figure><Example id="exa005"><Heading>Example 5</Heading><Paragraph>My half-litre measuring jug is marked off in divisions of 100 ml, with subdivisions of 20 ml. I want to measure out 420 cc, but the only conversion table I have tells me that a litre is one cubic decimetre. (One decimetre is a tenth of a metre.) How many cubic centimetres are there in a litre? Can I use the measuring jug for 420 cc?</Paragraph><Figure id="figi060"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i060i.jpg" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i060i.jpg" x_folderhash="eb44170e" x_contenthash="c9060adb" x_imagesrc="mu120_a_i060i.jpg" x_imagewidth="153" x_imageheight="340"/></Figure><Answer><!--<SubHeading>Solution</SubHeading>--><Paragraph>There is one cubic decimetre in a litre, so 1 litre measures 1 dm × 1 dm × 1 dm (if shaped into a cube). (Note: 1 m = 10 dm = 100 cm.) There are 10 centimetres in a decimetre, so a 1 litre cube would measure</Paragraph><Paragraph>  10 cm × 10 cm × 10 cm = 1000 cm<sup>3</sup>.</Paragraph><Paragraph/><Paragraph>So 1 litre is 1000 cm<sup>3</sup>. This is a useful result. </Paragraph><Paragraph>But there are 1000 millilitres in a litre, so it turns out that a millilitre is the same as a cubic centimetre.</Paragraph><Paragraph>  1 ml = 1 cm<sup>3</sup>.</Paragraph><Paragraph>So I can use the jug to measure 420 ml, or 420 cc (or cm<sup>3</sup>).</Paragraph><Paragraph>(Note: 1 cubic centimetre can be written as 1 cc or 1 cm<sup>3</sup>.)</Paragraph></Answer></Example><SubSection id="sec001_004_001"><Title>1.4.1 Try some yourself</Title><Activity id="act008"><Heading>Activity 8</Heading><Question><Paragraph>If a litre is one cubic decimetre, how many litres are there in a cubic metre?</Paragraph></Question><Answer><Paragraph>Since a litre is one cubic decimeter, the question is asking how may cubic decimetres are in a cubic metre.</Paragraph><Paragraph>1 metre = 10 decimetres</Paragraph><Paragraph>so 1 m<sup>3</sup> = 10<sup>3</sup> cubic decimetres.</Paragraph><Paragraph>Hence there are 1000 litres in a cubic metre.</Paragraph></Answer></Activity><Activity id="act009"><Heading>Activity 9</Heading><Question><Paragraph>Find the following without using your calculator, as an estimate for the calculator work in the next question.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) (<sup>−</sup>1)<sup>3</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 3<sup>3</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 100<sup>3</sup></Paragraph></ListItem><ListItem><Paragraph>(d) 0.1<sup>3</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) (<sup>−</sup>1)<sup>3</sup> = <sup>−</sup>1 × <sup>−</sup>1 × <sup>−</sup>1 = 1 × <sup>−</sup>1 = <sup>−</sup>1</Paragraph></ListItem><ListItem><Paragraph>(b) 3<sup>3</sup> = 3 × 3 × 3 = 9 × 3 = 27</Paragraph></ListItem><ListItem><Paragraph>(c) 100<sup>3</sup> = 100 × 100 × 100 = 10 000 × 100 = 1000 000 (a million)</Paragraph></ListItem><ListItem><Paragraph>(d) <InlineFigure><Image height="" movedownby="10" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si137e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si137e.gif" x_folderhash="eb44170e" x_contenthash="7244e8b3" x_imagesrc="mu120_a_si137e.gif" x_imagewidth="342" x_imageheight="22"/></InlineFigure></Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act010"><Heading>Activity 10</Heading><Question><Paragraph>Use your calculator to find the following.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) (<sup>−</sup>1.2)<sup>3</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 3.3<sup>3</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 101<sup>3</sup></Paragraph></ListItem><ListItem><Paragraph>(d) 0.121<sup>3</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) Estimate: (<sup>−</sup>1)<sup>3</sup> = <sup>−</sup>1.</Paragraph><Paragraph>Calculate: (<sup>−</sup>1.2)<sup>3</sup> = <sup>−</sup>1.728.</Paragraph></ListItem><ListItem><Paragraph>(b) Estimate: 3<sup>3</sup> = 27.</Paragraph><Paragraph>Calculate: 3.3<sup>3</sup> = 35.937.</Paragraph></ListItem><ListItem><Paragraph>(c) Estimate: 100<sup>3</sup> = 1000 000.</Paragraph><Paragraph>Calculate: 101<sup>3</sup> = 1030 301.</Paragraph></ListItem><ListItem><Paragraph>(d) Estimate: .1<sup>3</sup> = .001.</Paragraph><Paragraph>Calculate: 0.121<sup>3</sup> = 0.00177 (3 s.f.)</Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act011"><Heading>Activity 11</Heading><Question><Paragraph> What are the following?</Paragraph><UnNumberedList><ListItem><Paragraph>(a) <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i305e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i305e.gif" x_folderhash="eb44170e" x_contenthash="b27ea831" x_imagesrc="mu120_a_i305e.gif" x_imagewidth="15" x_imageheight="16"/></InlineFigure></Paragraph></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(b) <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i306e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i306e.gif" x_folderhash="eb44170e" x_contenthash="a7b38521" x_imagesrc="mu120_a_i306e.gif" x_imagewidth="41" x_imageheight="16"/></InlineFigure></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i305e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i305e.gif" x_folderhash="eb44170e" x_contenthash="b27ea831" x_imagesrc="mu120_a_i305e.gif" x_imagewidth="15" x_imageheight="16"/></InlineFigure> = 1 since 1<sup>3</sup> = 1.</Paragraph></ListItem><ListItem><Paragraph>(b) <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i306e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i306e.gif" x_folderhash="eb44170e" x_contenthash="a7b38521" x_imagesrc="mu120_a_i306e.gif" x_imagewidth="41" x_imageheight="16"/></InlineFigure> = 10 since 10<sup>3</sup> = 1000.</Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act012"><Heading>Activity 12</Heading><Question><Paragraph> Find the volume of a one-foot cube in cubic metres (1 foot = 30.48 cm). Estimate your answer first. Round your answer to three decimal places.</Paragraph></Question><Answer><Paragraph>To estimate an answer, choose a simple approximation, say</Paragraph><Paragraph>1 foot <InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 30 cm = 0.3 m.</Paragraph><Paragraph>Then 1 foot cubed <InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> (0.3)<sup>3</sup> = 0.027 m<sup>3</sup>.</Paragraph><Paragraph>More accurately, 1 foot = 30.48 cm = 0.3048 m.</Paragraph><Paragraph>So 1 foot cubed = (0.3048)<sup>3</sup> = 0.028 m<sup>3</sup> to three d.p.</Paragraph></Answer></Activity><Activity id="act013"><Heading>Activity 13</Heading><Question><Paragraph>Without using your calculator, find the following, as estimates for the calculator work in Question 7.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 9<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 4<sup>3</sup></Paragraph></ListItem><ListItem><Paragraph>(c) <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i279e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i279e.gif" x_folderhash="eb44170e" x_contenthash="57c45eb8" x_imagesrc="mu120_a_i279e.gif" x_imagewidth="25" x_imageheight="15"/></InlineFigure></Paragraph></ListItem><ListItem><Paragraph>(d) <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i280e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i280e.gif" x_folderhash="eb44170e" x_contenthash="51fea007" x_imagesrc="mu120_a_i280e.gif" x_imagewidth="28" x_imageheight="39"/></InlineFigure></Paragraph></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(e) (<sup>−</sup>3)<sup>2</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 9<sup>2</sup> = 9 × 9 = 81</Paragraph></ListItem><ListItem><Paragraph>(b) 4<sup>3</sup> = 4 × 4 × 4 = 16 × 4 = 64</Paragraph></ListItem><ListItem><Paragraph>(c) <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i279e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i279e.gif" x_folderhash="eb44170e" x_contenthash="57c45eb8" x_imagesrc="mu120_a_i279e.gif" x_imagewidth="25" x_imageheight="15"/></InlineFigure> = 8 (since 8<sup>2</sup> = 64)</Paragraph></ListItem><ListItem><Paragraph>(d) <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i285e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i285e.gif" x_folderhash="eb44170e" x_contenthash="e3ac780f" x_imagesrc="mu120_a_i285e.gif" x_imagewidth="97" x_imageheight="39"/></InlineFigure></Paragraph></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(e) (<sup>−</sup>3)<sup>2</sup> = <sup>−</sup>3 × <sup>−</sup>3 = 9</Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act014"><Heading>Activity 14</Heading><Question><Paragraph> Use your calculator to find:</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 9.42<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 3.65<sup>3</sup></Paragraph></ListItem><ListItem><Paragraph>(c) <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i281e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i281e.gif" x_folderhash="eb44170e" x_contenthash="3c33e2c5" x_imagesrc="mu120_a_i281e.gif" x_imagewidth="24" x_imageheight="15"/></InlineFigure></Paragraph></ListItem><ListItem><Paragraph>(d) 0.33<sup>3</sup></Paragraph></ListItem><ListItem><Paragraph>(e) (<sup>−</sup>2.713)<sup>2</sup></Paragraph></ListItem></UnNumberedList><Paragraph>Use your answers to the previous question as rough checks. Round your answers to four decimal places.</Paragraph></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 9.42<sup>2</sup> = 88.7364</Paragraph></ListItem><ListItem><Paragraph>(b) 3.65<sup>3</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 48.6271</Paragraph></ListItem><ListItem><Paragraph>(c) <InlineFigure><Image height="" movedownby="1" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i281e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i281e.gif" x_folderhash="eb44170e" x_contenthash="3c33e2c5" x_imagesrc="mu120_a_i281e.gif" x_imagewidth="24" x_imageheight="15"/></InlineFigure><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 8.3666</Paragraph></ListItem><ListItem><Paragraph>(d) 0.33<sup>3</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 0.0359 (check this by calculating <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i287e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i287e.gif" x_folderhash="eb44170e" x_contenthash="8289f9f4" x_imagesrc="mu120_a_i287e.gif" x_imagewidth="14" x_imageheight="27"/></InlineFigure>, the estimate from 3(d) above, as a decimal.</Paragraph></ListItem><ListItem><Paragraph>(e) (<sup>−</sup>2.713)<sup>2</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 7.3604 (N.B. To get this answer on a calculator, remember the brackets.)</Paragraph></ListItem></UnNumberedList></Answer></Activity></SubSection></Section></Session><Session id="sec002"><Title>2 Powers</Title><Section id="sec002_001"><Title>2.1 The impact of a power</Title><Paragraph>Here is a tale based on an ancient Eastern legend, which gives an idea of the impact of raising a number to a power.</Paragraph><Example id="exa006"><Heading>Example 6</Heading><Paragraph>A long time ago there lived a very rich king whose son's life was saved by a poor old beggar woman. The king was naturally very grateful to the woman, so he offered to give her anything that she wanted. Much to the king's surprise the old lady just asked for two bags of rice. When asked why she specifically wanted the rice, she explained that she would like to have her son to stay and that if she had some rice she would be able to feed him. The king felt that this was far too small a reward so he asked if there were any other members of her family that she might like to have to stay. She replied that she would like to have her two daughters the following week, so four bags of rice then would be a great help. The king agreed to this and suggested that she might like to think of having more of her family to stay. He said he would be prepared to double the number of bags he gave her each week. At this point his accountant got very agitated and asked him to consider very carefully what he was offering! What was he worried about?</Paragraph><Answer><!--<SubHeading>Solution</SubHeading>--><Paragraph>In order to decide if the king was being exceptionally generous, you need to look at exactly what he was proposing. In the beginning the numbers are quite small, 2 bags of rice in the first week, 4 bags in the second, then 8 in the third, 16 in the fourth, 32 in the fifth and so on. </Paragraph><Paragraph>  Week 1: 2 bags of rice = 2</Paragraph><Paragraph>  Week 2: 2 × 2 bags of rice = 4</Paragraph><Paragraph>  Week 3: 2 × 2 × 2 bags of rice = 8</Paragraph><Paragraph>  Week 4: 2 × 2 × 2 × 2 bags of rice = 16</Paragraph><Paragraph>  Week 5: 2 × 2 × 2 × 2 × 2 bags of rice = 32</Paragraph><Paragraph>  <InlineFigure><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i062i.jpg" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i062i.jpg" x_folderhash="eb44170e" x_contenthash="dc387d03" x_imagesrc="mu120_a_i062i.jpg" x_imagewidth="3" x_imageheight="20"/></InlineFigure></Paragraph><Paragraph>However, to get a feel for how the numbers are growing, look at them in another way.</Paragraph><Paragraph>It is not particularly convenient to write out all these 2s, particularly if you want to go on and look at the situation in week 52, say, i.e. a year later. However, there is a short and neater way of expressing these numbers.</Paragraph><Paragraph>You can write 2 × 2 = 2<sup>2</sup> = 4 and 2 × 2 × 2 = 2<sup>3</sup> = 8.</Paragraph><Paragraph>In a similar manner, in week 4 you can write 2 × 2 × 2 × 2 = 2<sup>4</sup> = 16, … and in week 10, when there are ten twos multiplied together, you can write 2<sup>10</sup>. Sometimes you may find it written 2 ^ 10 (^ is the ‘power of’ sign).</Paragraph><Paragraph>In week 1, when the number of bags is just 2, you can write this as 2<sup>1</sup>.</Paragraph><Paragraph>These numbers can be worked out on your calculator. Check each of 2<sup>4</sup>, 2<sup>5</sup> and 2<sup>10</sup> using your calculator.</Paragraph><Paragraph>You should find that 2<sup>10</sup> = 1024 and so see what the accountant was worried about.</Paragraph></Answer></Example><SubSection id="sec002_001_001"><Title>2.1.1 Try some yourself</Title><Activity id="act015"><Heading>Activity 15</Heading><Question><Paragraph> The size of a population of micro-organisms doubles every hour. If there are two of these creatures to start with, how many will there be after five hours?</Paragraph></Question><Answer><Paragraph>After one hour there are 2 × 2 = 4 micro-organisms.</Paragraph><Paragraph>After two hours there are 2 × 4 = 8, or 2 × 2 × 2 = 2<sup>3</sup>.</Paragraph><Paragraph><InlineFigure><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i062i.jpg" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i062i.jpg" x_folderhash="eb44170e" x_contenthash="dc387d03" x_imagesrc="mu120_a_i062i.jpg" x_imagewidth="3" x_imageheight="20"/></InlineFigure></Paragraph><Paragraph>After five hours there are 2 × 32 = 64, or 2 × 2 × 2 × 2 × 2 × 2 = 2<sup>6</sup>.</Paragraph><Paragraph>So there will be 2<sup>6</sup> = 64 after five hours.</Paragraph><Paragraph>(Note: if you gave 32 as your answer, maybe you forgot that there were 2 organisms to start with.)</Paragraph></Answer></Activity></SubSection></Section><Section id="sec002_002"><Title>2.2 Power notation</Title><Paragraph>The notation in <CrossRef idref="exa006">Example 6</CrossRef> is called <b>power notation</b>, or <b>index notation</b>. In a number such as 2<sup>5</sup>, the 5 is called the <b>power</b>, or <b>index</b>, of the number.</Paragraph><Paragraph>The squares are particular examples of powers: 9<sup>2</sup>, for example, can be thought of as ‘9 to the power 2’.</Paragraph><Paragraph>For most numbers, calculating powers by hand soon becomes tedious: while you might be quite happy to find 2<sup>5</sup> or 9<sup>2</sup>, it would take a long and fairly dull time to find 2<sup>50</sup> or 9<sup>20</sup> by hand. So you will be using your calculator for most calculations involving powers, even when the numbers themselves are quite simple. However, there is one number whose powers are quite easy to find, namely 10. For example:</Paragraph><Paragraph>  one hundred = 10 × 10 = 10<sup>2</sup> = 100;</Paragraph><Paragraph>  one thousand = 10 × 10 × 10 = 10<sup>3</sup> = 1000;</Paragraph><Paragraph>  one million = 10 × 10 × 10 × 10 × 10 × 10 = 10<sup>6</sup> = 1000 000.</Paragraph><Paragraph>In the same way that 2 can be written as 2<sup>1</sup> so 10 can be written as 10<sup>1</sup>.</Paragraph><Paragraph>It is also easy to find powers of 1 and 0. 1 × 1 × 1 × … = 1 and 0 × 0 × 0 = 0.</Paragraph><Example id="exa007"><Heading>Example 7</Heading><Paragraph>The headings on the place value tables in the OpenLearn course <a href="http://www.open.edu/openlearn/science-maths-technology/mathematics-and-statistics/mathematics-education/numbers-units-and-arithmetic/content-section-0?utm_source=openlearn&amp;utm_campaign=ol&amp;utm_medium=ebook"><i xml:space="preserve">Numbers, units and arithmetic</i></a> are tens, hundreds, thousands etc. … Write these as powers of ten. What do you think the units columns heading would be as a power of ten?</Paragraph><Answer><!--<SubHeading>Solution</SubHeading>--><Table id="utab020"><TableHead/><tbody><tr><td class="TableLeft">ten</td><td class="TableLeft">= 10 = 10<sup>1</sup></td></tr><tr><td class="TableLeft">hundred</td><td class="TableLeft">= 100 = 10<sup>2</sup></td></tr><tr><td class="TableLeft">thousand</td><td class="TableLeft">= 1000 = 10<sup>3</sup></td></tr><tr><td class="TableLeft">ten thousand</td><td class="TableLeft">= 10 000 = 10<sup>4</sup></td></tr><tr><td class="TableLeft">hundred thousands</td><td class="TableLeft">= 100 000 = 10<sup>5</sup></td></tr><tr><td class="TableLeft">million</td><td class="TableLeft">= 1000 000 = 10<sup>6</sup></td></tr></tbody><SourceReference/></Table><Paragraph>The power of ten increases for each column. So to be consistent, the units column should be 10<sup>0</sup>. Putting 10<sup>0</sup> into a calculator gives 10<sup>0</sup> = 1. So the units column is 1 = 10<sup>0</sup>.</Paragraph></Answer></Example><SubSection id="sec002_002_001"><Title>2.2.1 Try some yourself</Title><Activity id="act016"><Heading>Activity 16</Heading><Question><Paragraph>Find the following powers by hand, as estimates for calculator work.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 10<sup>7</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 10<sup>8</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 3<sup>4</sup></Paragraph></ListItem><ListItem><Paragraph>(d) (<sup>−</sup>2)<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(e) (<sup>−</sup>2)<sup>3</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 10<sup>7</sup> = 10 000 000</Paragraph></ListItem><ListItem><Paragraph>(b) 10<sup>8</sup> = 100 000 000</Paragraph></ListItem><ListItem><Paragraph>(c) 3<sup>4</sup> = 3 × 3 × 3 × 3 = 27 × 3 = 81</Paragraph></ListItem><ListItem><Paragraph>(d) (<sup>−</sup>2)<sup>2</sup> = <sup>−</sup>2 × <sup>−</sup>2 = 4</Paragraph></ListItem><ListItem><Paragraph>(e) (<sup>−</sup>2)<sup>3</sup> = 4 × <sup>−</sup>2 = <sup>−</sup>8</Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act017"><Heading>Activity 17</Heading><Question><Paragraph>Use your calculator to find the following and use your answers to the previous question as a check. Give your answers correct to 3 significant figures.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 11<sup>7</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 10.8<sup>8</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 3.14<sup>4</sup></Paragraph></ListItem><ListItem><Paragraph>(d) (<sup>−</sup>2.2)<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(e) (<sup>−</sup>2.01)<sup>3</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 11<sup>7</sup> = 19 487 171 <InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 19 500 000 (3 s.f.)</Paragraph></ListItem><ListItem><Paragraph>(b) 10.8<sup>8</sup> = 185 093 021 <InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 185 000 000 (3 s.f.)</Paragraph></ListItem><ListItem><Paragraph>(c) 3.14<sup>4</sup> = 97.21171216 <InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 97.2 (3 s.f.)</Paragraph></ListItem><ListItem><Paragraph>(d) (<sup>−</sup>2.2)<sup>2</sup> = 4.84</Paragraph></ListItem><ListItem><Paragraph>(e) <sup>−</sup>(2.01)<sup>3</sup> = <sup>−</sup>8.120601 <InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure><sup>−</sup>8.12 (3 s.f.)</Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act018"><Heading>Activity 18</Heading><Question><UnNumberedList><ListItem><Paragraph>(a) How many zeros are there in 10<sup>12</sup> when written out in full? Work out a rule for finding the number of zeros in any positive whole number power of 10.</Paragraph></ListItem><ListItem><Paragraph>(b) Your answers to parts (d) and (e) of Question 1 may have suggested a rule for powers of negative numbers, depending on whether the power is odd or even. What is the rule?</Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) There are 12 zeros in 10<sup>12</sup>. The number of zeros for a positive power of 10 is the same as the power.</Paragraph></ListItem><ListItem><Paragraph>(b) An odd power of a negative number is negative. An even power of a negative number is positive.</Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act019"><Heading>Activity 19</Heading><Question><Paragraph> Hamsters of a particular kind, left to breed in a suitable environment, double their population every month. If a friend of yours, who is thinking of breeding these hamsters, started with one pair (male and female), what population might she expect in a year's time (assuming she keeps them all)?</Paragraph></Question><Answer><Paragraph>After 0 months (i.e. at the start) there are 2 hamsters = 2</Paragraph><Paragraph>After 1 month there are 2 × 2 hamsters, i.e. 2<sup>2</sup> = 4</Paragraph><Paragraph>After 2 months there are 2 × 2 × 2 hamsters, i.e. 2<sup>3</sup> = 8</Paragraph><Paragraph>So after 12 months there are 2<sup>13</sup> = 8192 hamsters.</Paragraph></Answer></Activity><Activity id="act020"><Heading>Activity 20</Heading><Question><Paragraph> A ploughed field has been left abandoned. It has one weed in the middle. The weed is an annual plant and its flower produces about 1000 seeds. If a tenth of these seeds germinate to produce one flower each in a year's time, estimate the possible number of dandelion flowers in the field if it is abandoned for five years. (You can assume that no other factors affect the growth of the weeds during this time).</Paragraph></Question><Answer><Paragraph><InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si141e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si141e.gif" x_folderhash="eb44170e" x_contenthash="ab04b952" x_imagesrc="mu120_a_si141e.gif" x_imagewidth="13" x_imageheight="27"/></InlineFigure> of 1000 = 100</Paragraph><Paragraph>So 100 seeds per flower germinate each year.</Paragraph><Paragraph>At 0 years there is 1 weed.</Paragraph><Paragraph>After 1 year there are 1 × 100 = 100 weeds (which can be written as 100<sup>1</sup>).</Paragraph><Paragraph>After 2 years there are</Paragraph><Paragraph>100 × 100 = 100<sup>2</sup> = 10 000 weeds.</Paragraph><Paragraph>So after 5 years an estimate is</Paragraph><Paragraph>100<sup>5</sup> = 10 000 000 000 weeds (or 10 billion).</Paragraph></Answer></Activity><Activity id="act021"><Heading>Activity 21</Heading><Question><Paragraph> Cells in a laboratory culture divide into two every day, given sufficient nutrient. If there were five cells on day one, how many would there be on day ten?</Paragraph></Question><Answer><Paragraph>On day 1 there are 5 cells</Paragraph><Paragraph>On day 2 there are 5 × 2 = 10 cells</Paragraph><Paragraph>On day 3 there are 5 × 2 × 2 = 5 × 2<sup>2</sup> = 20 cells</Paragraph><Paragraph>On day 4 there are 5 × 2 × 2 × 2 = 5 × 2<sup>3</sup> = 40 cells.</Paragraph><Paragraph>So on day 10 there are 5 × 2<sup>9</sup> = 5 × 512 = 2560 cells.</Paragraph></Answer></Activity></SubSection></Section><Section id="sec002_003"><Title>2.3 Multiplying powers</Title><Paragraph>Powers of ten can be used to investigate what happens when two powers of the same number are multiplied together. For example, consider multiplying 10 by 100:</Paragraph><Equation id="ueqn039"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u039e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u039e.gif" x_folderhash="eb44170e" x_contenthash="9047c166" x_imagesrc="mu120_a_u039e.gif" x_imagewidth="167" x_imageheight="126"/></Equation><Paragraph>A billion is a thousand million. In terms of powers this is:</Paragraph><Equation id="ueqn040"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u040e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u040e.gif" x_folderhash="eb44170e" x_contenthash="331e7cb4" x_imagesrc="mu120_a_u040e.gif" x_imagewidth="381" x_imageheight="126"/></Equation><Paragraph>so a billion is 10<sup>9</sup> or 1000 000 000.</Paragraph><Paragraph>(An American billion is a thousand million. In UK a billion used to be a million million, but now the American billion is the standard usage.)</Paragraph><Paragraph>Note: The number of zeros in the whole number power of ten is the same as the power.</Paragraph><Paragraph>In the above calculations, 10<sup>1</sup> × 10<sup>2</sup> = 10<sup>3</sup> and 10<sup>3</sup> × 10<sup>6</sup> = 10<sup>9</sup>, and the way these have been worked out shows that, when you <i>multiply</i> numbers expressed as powers of ten, you <i>add</i> the powers.</Paragraph><Paragraph>Powers of 10 were used because they are easy to work with, but you can just as easily show that multiplying powers of the same number always means adding the powers. For example:</Paragraph><Equation id="ueqn041"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u041e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u041e.gif" x_folderhash="eb44170e" x_contenthash="8e908854" x_imagesrc="mu120_a_u041e.gif" x_imagewidth="290" x_imageheight="52"/></Equation><Paragraph>so 7<sup>2</sup> × 7<sup>3</sup> = 7<sup>2+3</sup> = 7<sup>5</sup>. Check this on your calculator!</Paragraph><Box id="box021"><Paragraph>To multiply two powers of the same number, add the powers.</Paragraph></Box><SubSection id="sec002_003_001"><Title>2.3.1 Try some yourself</Title><Activity id="act022"><Heading>Activity 22</Heading><Question><Paragraph> Write the following as one number to a single power:</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 2<sup>3</sup> × 2<sup>4</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 3<sup>2</sup> × 3<sup>4</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 4<sup>2</sup> × 4<sup>3</sup> × 4<sup>4</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 2<sup>3</sup> × 2<sup>4</sup> = 2<sup>(3 + 4)</sup> = 2<sup>7</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 3<sup>2</sup> × 3<sup>4</sup> = 3<sup>(2 + 4)</sup> = 3<sup>6</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 4<sup>2</sup> × 4<sup>3</sup> × 4<sup>4</sup> = 4<sup>(2 + 3 + 4)</sup> = 4<sup>9</sup></Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act023"><Heading>Activity 23</Heading><Question><Paragraph> Without using your calculator, find the following, as estimates for calculation work in the next question.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) (<sup>−</sup>1)<sup>5</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 3<sup>4</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) (<sup>−</sup>1)<sup>5</sup> = <sup>−</sup>1 (any odd power of <sup>−</sup>1 is <sup>−</sup>1)</Paragraph></ListItem><ListItem><Paragraph>(b) 3<sup>4</sup> = 3 × 3 × 3 × 3 = 81</Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act024"><Heading>Activity 24</Heading><Question><Paragraph> Use your calculator to find the following.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) (<sup>−</sup>1.3)<sup>5</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 3.2<sup>4</sup></Paragraph></ListItem></UnNumberedList><Paragraph>(Use your answers to the previous question as rough checks.) Round your answers to four decimal places.</Paragraph></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) (<sup>−</sup>1.3)<sup>5</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure><sup>−</sup>3.7129</Paragraph></ListItem><ListItem><Paragraph>(b) 3.2<sup>4</sup> = 104.8576</Paragraph></ListItem></UnNumberedList></Answer></Activity></SubSection></Section><Section id="sec002_004"><Title>2.4 Dividing powers</Title><Paragraph>Now consider division in the same way. For example:</Paragraph><Equation id="ueqn042"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u042e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u042e.gif" x_folderhash="eb44170e" x_contenthash="cef57965" x_imagesrc="mu120_a_u042e.gif" x_imagewidth="411" x_imageheight="82"/></Equation><Paragraph>So 10<sup>3</sup> ÷ 10<sup>2</sup> = 10<sup>1</sup> and 10<sup>6</sup> ÷ 10<sup>2</sup> = 10<sup>4</sup>, which suggests that dividing the powers of ten means subtracting the powers. You can see that the two tens underneath have cancelled with two of the tens on top in each case, which shows why the number of tens underneath is subtracted from the number on top. This argument applies equally well to any number. For example:</Paragraph><Equation id="ueqn043"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u043e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u043e.gif" x_folderhash="eb44170e" x_contenthash="bf77f75f" x_imagesrc="mu120_a_u043e.gif" x_imagewidth="256" x_imageheight="65"/></Equation><Paragraph>Work out 7<sup>5</sup> ÷ 7<sup>3</sup> on your calculator to check this.</Paragraph><Box id="box022"><Paragraph>To divide two powers of the same number, subtract the powers.</Paragraph></Box><SubSection id="sec002_004_001"><Title>2.4.1 Try some yourself</Title><Activity><Heading>Activity 25</Heading><Question id="act025"><Paragraph> Write the following as a number to a single power:</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 2<sup>6</sup> ÷ 2<sup>2</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 10<sup>10</sup> ÷ 10<sup>7</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 7<sup>8</sup> ÷ 7<sup>4</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 2<sup>6</sup> ÷ 2<sup>2</sup> = 2<sup>(6 − 2)</sup> = 2<sup>4</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 10<sup>10</sup> ÷ 10<sup>7</sup> = 10<sup>(10 − 7)</sup> = 10<sup>3</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 7<sup>8</sup> ÷ 7<sup>4</sup> = 7<sup>(8 − 4)</sup> = 7<sup>4</sup></Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act026"><Heading>Activity 26</Heading><Question><Paragraph> Express as powers of ten</Paragraph><UnNumberedList><ListItem><Paragraph>(a) a million</Paragraph></ListItem><ListItem><Paragraph>(b) a thousand</Paragraph></ListItem><ListItem><Paragraph>(c) a million divided by a thousand</Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) a million = 1 000 000 = 10<sup>6</sup></Paragraph></ListItem><ListItem><Paragraph>(b) a thousand = 1 000 = 10<sup>3</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 10<sup>6</sup> divided by 10<sup>3</sup> = 10<sup>6–3</sup> = 10<sup>3</sup> = a thousand</Paragraph></ListItem></UnNumberedList></Answer></Activity></SubSection></Section><Section id="sec002_005"><Title>2.5 The power zero</Title><Paragraph>Now, what happens if you divide a number by itself? You should get the answer 1. For example</Paragraph><Paragraph><InlineFigure><Image height="" movedownby="4" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i309e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i309e.gif" x_folderhash="eb44170e" x_contenthash="c6e06fbb" x_imagesrc="mu120_a_i309e.gif" x_imagewidth="281" x_imageheight="36"/></InlineFigure></Paragraph><Paragraph>so 10<sup>0</sup> must equal 1. This must be true for any number (except for 0, because there is a problem in defining 0<sup>0</sup>). So, for example, 7<sup>0</sup> = 1, 123<sup>0</sup> = 1, 1000<sup>0</sup> = 1. It even works for negative and decimal numbers. Check a few numbers on your calculator to see that raising to the power 0 gives 1.</Paragraph><Box id="box23"><Paragraph>Any non-zero number raised to the power 0 is 1.</Paragraph></Box><SubSection id="sec002_005_001"><Title>2.5.1 Try some yourself</Title><Activity id="act027"><Heading>Activity 27</Heading><Question><Paragraph> What are the following?</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 1<sup>0</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 0<sup>1</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 2<sup>0</sup></Paragraph></ListItem><ListItem><Paragraph>(d) 0<sup>2</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 1<sup>0</sup> = 1</Paragraph></ListItem><ListItem><Paragraph>(b) 0<sup>1</sup> = 0</Paragraph></ListItem><ListItem><Paragraph>(c) 2<sup>0</sup> = 1</Paragraph></ListItem><ListItem><Paragraph>(d) 0<sup>2</sup> = 0 × 0 = 0</Paragraph></ListItem></UnNumberedList></Answer></Activity></SubSection></Section><Section id="sec002_006"><Title>2.6 Negative powers</Title><Paragraph>Now look at what happens when the power is negative. What does 10<sup>−3</sup> mean? What is the result of the following calculation?</Paragraph><Paragraph>100 ÷ 100 000</Paragraph><Paragraph>What you are actually being asked to find is:</Paragraph><Equation id="ueqn044"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u044e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u044e.gif" x_folderhash="eb44170e" x_contenthash="2fba95dd" x_imagesrc="mu120_a_u044e.gif" x_imagewidth="163" x_imageheight="28"/></Equation><Paragraph>But look at the calculation again. Using the rule for the division of powers of numbers gives:</Paragraph><Paragraph>10<sup>2</sup> ÷ 10<sup>5</sup> = 10<sup>2−5</sup> = 10<sup>−3</sup></Paragraph><Paragraph>So 10<sup>−3</sup> = 0.001. But you can also write this result as:</Paragraph><Equation id="ueqn045"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u045e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u045e.gif" x_folderhash="eb44170e" x_contenthash="d7c4ecc3" x_imagesrc="mu120_a_u045e.gif" x_imagewidth="173" x_imageheight="31"/></Equation><Paragraph>This means that 10<sup>−3</sup> can be thought of as 1 divided by 10<sup>3</sup>.</Paragraph><Paragraph><InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i312e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i312e.gif" x_folderhash="eb44170e" x_contenthash="6286d059" x_imagesrc="mu120_a_i312e.gif" x_imagewidth="317" x_imageheight="27"/></InlineFigure></Paragraph><Paragraph>This result is true for all negative powers, not just powers of ten. For example:</Paragraph><Equation id="ueqn046"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u046e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u046e.gif" x_folderhash="eb44170e" x_contenthash="436a76a9" x_imagesrc="mu120_a_u046e.gif" x_imagewidth="141" x_imageheight="31"/></Equation><Paragraph>One over any number is called the <b>reciprocal</b> of the number.</Paragraph><Paragraph>For example, the reciprocal of 10 is <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i314e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i314e.gif" x_folderhash="eb44170e" x_contenthash="ab04b952" x_imagesrc="mu120_a_i314e.gif" x_imagewidth="13" x_imageheight="27"/></InlineFigure> = 10<sup>−1</sup> and the reciprocal of 100 is <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i315e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i315e.gif" x_folderhash="eb44170e" x_contenthash="d9a6ddcd" x_imagesrc="mu120_a_i315e.gif" x_imagewidth="20" x_imageheight="27"/></InlineFigure> = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i316e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i316e.gif" x_folderhash="eb44170e" x_contenthash="eba07e4c" x_imagesrc="mu120_a_i316e.gif" x_imagewidth="22" x_imageheight="30"/></InlineFigure> = 10<sup>−2</sup></Paragraph><Box id="box024"><Paragraph>A number raised to a negative power is the reciprocal of the number raised to the corresponding positive power.</Paragraph></Box><Paragraph>So 10<sup>−5</sup> = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i317e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i317e.gif" x_folderhash="eb44170e" x_contenthash="1d19f933" x_imagesrc="mu120_a_i317e.gif" x_imagewidth="22" x_imageheight="30"/></InlineFigure> = 0.00001.</Paragraph><Paragraph/><Example id="exa008"><Heading>Example 8</Heading><Paragraph>The decimal place value table columns are headed tenths, hundredths, thousandths etc. Write these as powers of ten.</Paragraph><Answer><!--<SubHeading>Solution</SubHeading>--><Paragraph>  a tenth = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i314e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i314e.gif" x_folderhash="eb44170e" x_contenthash="ab04b952" x_imagesrc="mu120_a_i314e.gif" x_imagewidth="13" x_imageheight="27"/></InlineFigure> =10<sup>−1</sup></Paragraph><Paragraph>  a hundredth = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i315e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i315e.gif" x_folderhash="eb44170e" x_contenthash="d9a6ddcd" x_imagesrc="mu120_a_i315e.gif" x_imagewidth="20" x_imageheight="27"/></InlineFigure> = 10<sup>−2</sup></Paragraph><Paragraph>  a thousandth = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i320e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i320e.gif" x_folderhash="eb44170e" x_contenthash="8f29f044" x_imagesrc="mu120_a_i320e.gif" x_imagewidth="27" x_imageheight="27"/></InlineFigure> = 10<sup>−3</sup></Paragraph><Paragraph/><Paragraph>So the headings of the place value table are all powers of ten. To the left of the units they are positive powers, the units column is 10<sup>0</sup>, and to the right the column headings are negative powers of ten.</Paragraph><Paragraph/><Figure id="figi063"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i063i.jpg" webthumbnail="false" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i063i.jpg" x_folderhash="eb44170e" x_contenthash="50888329" x_imagesrc="mu120_a_i063i.jpg" x_imagewidth="511" x_imageheight="93"/></Figure></Answer></Example><Paragraph>Notice that</Paragraph><Equation id="ueqn047"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u047e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u047e.gif" x_folderhash="eb44170e" x_contenthash="5ec10090" x_imagesrc="mu120_a_u047e.gif" x_imagewidth="125" x_imageheight="64"/></Equation><Paragraph>The negative power indicates the position of the decimal point — how many times it has moved to the left from 10<sup>0</sup> = 1.</Paragraph><Paragraph>10<sup>−1</sup> = 0.1 (move one to the left); 10<sup>−2</sup> = 0.01 (move 2 to the left) etc.</Paragraph><SubSection id="sec002_006_001"><Title>2.6.1 Try some yourself</Title><Activity id="act028"><Heading>Activity 28</Heading><Question><Paragraph> Find each of the following by hand, giving your answers both as a power of ten and as a decimal number. You will use these answers as a check on your calculator work in the next question.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 10<sup>−2</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 10<sup>2</sup> × 10<sup>3</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 10<sup>7</sup> ÷ 10<sup>4</sup></Paragraph></ListItem><ListItem><Paragraph>(d) 10<sup>4</sup> ÷ 10<sup>7</sup></Paragraph></ListItem><ListItem><Paragraph>(e) 2<sup>−2</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 10<sup>−2</sup> = 0.01</Paragraph></ListItem><ListItem><Paragraph>(b) 10<sup>2</sup> × 10<sup>3</sup> = 10<sup>2 + 3</sup> = 10<sup>5</sup> = 100 000</Paragraph></ListItem><ListItem><Paragraph>(c) 10<sup>7</sup> ÷ 10<sup>4</sup> = 10<sup>7 − 4</sup> = 10<sup>3</sup> = 1000</Paragraph></ListItem><ListItem><Paragraph>(d) 10<sup>4</sup> ÷ 10<sup>7</sup> = 10<sup>4 − 7</sup> = 10<sup>–3</sup> = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i320e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i320e.gif" x_folderhash="eb44170e" x_contenthash="8f29f044" x_imagesrc="mu120_a_i320e.gif" x_imagewidth="27" x_imageheight="27"/></InlineFigure> = 0.001</Paragraph></ListItem><ListItem><Paragraph>(e) 2<sup>−2</sup> = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i307e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i307e.gif" x_folderhash="eb44170e" x_contenthash="7912a878" x_imagesrc="mu120_a_i307e.gif" x_imagewidth="15" x_imageheight="30"/></InlineFigure> = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i308e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i308e.gif" x_folderhash="eb44170e" x_contenthash="920eaded" x_imagesrc="mu120_a_i308e.gif" x_imagewidth="7" x_imageheight="27"/></InlineFigure> (=0.25)</Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act029"><Heading>Activity 29</Heading><Question><Paragraph> Evaluate the following, using your calculator and your answers from <CrossRef idref="act028">Question 1</CrossRef> as estimates.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 10.3<sup>−2</sup> (to four significant figures)</Paragraph></ListItem><ListItem><Paragraph>(b) 10.1<sup>2</sup> × 10.11<sup>3</sup> (to four significant figures)</Paragraph></ListItem><ListItem><Paragraph>(c) 10.112<sup>7</sup> ÷ 10.21<sup>4</sup> (to one decimal place)</Paragraph></ListItem><ListItem><Paragraph>(d) 10.12<sup>4</sup> ÷ 10.351<sup>7</sup> (to three significant figures)</Paragraph></ListItem><ListItem><Paragraph>(e) 2.2<sup>−2</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><Paragraph>Using <CrossRef idref="act028">Question 1</CrossRef> as a rough check, the calculator gives:</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 10.3<sup>−2</sup> = 0.009 426 (to 4 s.f.)</Paragraph></ListItem><ListItem><Paragraph>(b) 10.1<sup>2</sup> × 10.11<sup>3</sup> = 105 400 (to 4 s.f.)</Paragraph></ListItem><ListItem><Paragraph>(c) 10.112<sup>7</sup> ÷ 10.21<sup>4</sup> = 994.8 (to 1 d.p.)</Paragraph></ListItem><ListItem><Paragraph>(d) 10.12<sup>4</sup> ÷ 10.351<sup>7</sup> = 0.000824 (to 3 s.f.)</Paragraph></ListItem><ListItem><Paragraph>(e) 2.2<sup>−2</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 0.2066</Paragraph></ListItem></UnNumberedList><Paragraph>It is a good idea to get in the habit of estimating your answers, even if not specifically asked to do so.</Paragraph></Answer></Activity><Activity id="act030"><Heading>Activity 30</Heading><Question><Paragraph> Find each of the following by hand.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 1024<sup>0</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 1024<sup>1</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 5<sup>−1</sup></Paragraph></ListItem><ListItem><Paragraph>(d) 10<sup>−4</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 1024<sup>0</sup> = 1</Paragraph></ListItem><ListItem><Paragraph>(b) 1024<sup>1</sup> = 1024</Paragraph></ListItem><ListItem><Paragraph>(c) <InlineFigure><Image height="" movedownby="14" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si143e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si143e.gif" x_folderhash="eb44170e" x_contenthash="6228d64d" x_imagesrc="mu120_a_si143e.gif" x_imagewidth="123" x_imageheight="31"/></InlineFigure></Paragraph></ListItem><ListItem><Paragraph>(d) <InlineFigure><Image height="" movedownby="14" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si144e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si144e.gif" x_folderhash="eb44170e" x_contenthash="b0f06718" x_imagesrc="mu120_a_si144e.gif" x_imagewidth="205" x_imageheight="31"/></InlineFigure></Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act031"><Heading>Activity 31</Heading><Question><Paragraph> How many zeros are there after the decimal point in the number 10<sup>−6</sup>? How many zeros are there after the decimal point for any given negative power of 10?</Paragraph></Question><Answer><Paragraph>10<sup>−6</sup> = 0.000 001; there are five zeros after the decimal point. For any given negative power of 10, say 10﻿<sup>−(NUMBER)</sup> there is one fewer zero than NUMBER. This works for 10<sup>−1</sup>, too, since 10<sup>−1</sup> = 0.1, which has no zeros after the decimal point, i.e. one fewer than 1.</Paragraph></Answer></Activity><Activity id="act032"><Heading>Activity 32</Heading><Question><Paragraph> Try to answer the following questions</Paragraph><UnNumberedList><ListItem><Paragraph>(a) Explain why a negative power of a number is one divided by the corresponding positive power of that number. (<i>Hint</i>: remember that a number to the power zero is 1.)</Paragraph></ListItem><ListItem><Paragraph>(b) Use the power button on your calculator to find the following.</Paragraph><UnNumberedSubsidiaryList><SubListItem><Paragraph>(i) <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i321e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i321e.gif" x_folderhash="eb44170e" x_contenthash="dcf9108e" x_imagesrc="mu120_a_i321e.gif" x_imagewidth="9" x_imageheight="28"/></InlineFigure></Paragraph></SubListItem><SubListItem><Paragraph>(ii) <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i322e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i322e.gif" x_folderhash="eb44170e" x_contenthash="5971a666" x_imagesrc="mu120_a_i322e.gif" x_imagewidth="26" x_imageheight="31"/></InlineFigure></Paragraph></SubListItem></UnNumberedSubsidiaryList></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) Take an example, which makes the explanation easier than describing it in the abstract. Consider 10<sup>−6</sup>. Now <sup>−</sup>6 is just the same as 0 − 6, so 10<sup>−6</sup> = 10<sup>0−6</sup>. Using the rule for dividing powers, 10<sup>0−6</sup> = 10<sup>0</sup> ÷ 10<sup>6</sup>. But 10<sup>0</sup> = 1. So 10<sup>−6</sup> = 1 ÷ 10<sup>6</sup>. This argument would apply equally well to any number, since any number to the power 0 is 1. (Alternatively you may have started from the other end, for example, by showing that <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si145e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si145e.gif" x_folderhash="eb44170e" x_contenthash="94c707be" x_imagesrc="mu120_a_si145e.gif" x_imagewidth="22" x_imageheight="30"/></InlineFigure> = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si146e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si146e.gif" x_folderhash="eb44170e" x_contenthash="a1676429" x_imagesrc="mu120_a_si146e.gif" x_imagewidth="22" x_imageheight="35"/></InlineFigure> = 10<sup>0−6</sup> = 10<sup>−6</sup>.)</Paragraph></ListItem><ListItem><Paragraph>(b)</Paragraph><UnNumberedSubsidiaryList><SubListItem><Paragraph><InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120new.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120new.gif" x_folderhash="eb44170e" x_contenthash="7e5f3145" x_imagesrc="mu120new.gif" x_imagewidth="100" x_imageheight="40"/></InlineFigure></Paragraph></SubListItem><SubListItem><Paragraph><InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si147e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si147e.gif" x_folderhash="eb44170e" x_contenthash="cc629448" x_imagesrc="mu120_a_si147e.gif" x_imagewidth="114" x_imageheight="30"/></InlineFigure></Paragraph></SubListItem></UnNumberedSubsidiaryList></ListItem></UnNumberedList></Answer></Activity></SubSection></Section></Session><Session id="sec003"><Title>3 Scientific notation</Title><Section id="sec003_001"><Title>3.1 Expressing numbers in scientific notation</Title><Paragraph>Earlier you looked at place values for numbers, and why they were called powers of ten.</Paragraph><Table id="utab021"><TableHead/><tbody><tr><td class="TableLeft">Place value</td><td class="TableCentered">10 000</td><td class="TableCentered">1000</td><td class="TableCentered">100</td><td class="TableCentered">10</td><td class="TableCentered">1</td><td class="TableCentered">0.1</td><td class="TableCentered">0.01</td><td class="TableCentered">0.001</td><td class="TableCentered">0.0001</td><td class="TableCentered">0.000 01</td></tr><tr><td class="TableLeft">Power of ten</td><td class="TableCentered">10<sup>4</sup></td><td class="TableCentered">10<sup>3</sup></td><td class="TableCentered">10<sup>2</sup></td><td class="TableCentered">10<sup>1</sup></td><td class="TableCentered">10<sup>0</sup></td><td class="TableCentered">10<sup>−1</sup></td><td class="TableCentered">10<sup>−2</sup></td><td class="TableCentered">10<sup>−3</sup></td><td class="TableCentered">10<sup>−4</sup></td><td class="TableCentered">10<sup>−5</sup></td></tr></tbody><SourceReference/></Table><Paragraph/><Paragraph>Using this notation, very large numbers or small decimal numbers can be expressed in a particularly neat form. This is how scientific and graphics calculators display numbers which will not fit on the screen. This is illustrated by the following examples:</Paragraph><Paragraph>  10<sup>7</sup> = 10 000 000 so 25 000 000 = 2.5 × 10<sup>7</sup></Paragraph><Paragraph>  10<sup>−6</sup> = 0.000 001 so 0.000 0025 = 2.5 × 10<sup>−6</sup></Paragraph><Paragraph>A number expressed in this form is said to be in <b>scientific notation</b>. Any decimal number can be converted to scientific notation, which is</Paragraph><Figure id="figi064"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i064i.jpg" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i064i.jpg" x_folderhash="eb44170e" x_contenthash="bc4f945d" x_imagesrc="mu120_a_i064i.jpg" x_imagewidth="303" x_imageheight="72"/></Figure><Paragraph>A calculator automatically uses scientific notation when the answer to a calculation is very large or very small. For example, return to our tale of the king and the bags of rice. In week 52 the woman would receive 2<sup>52</sup> bags. Calculate this on your calculator. You should get 4.503 599 627 × 10<sup>15</sup>. (This number may be displayed as 4.503 599 627 E 15.) To get a feel for how big this number is, i.e. for how many bags of rice the king would need to provide a year later, look at some other numbers in scientific notation:</Paragraph><Paragraph>  Great Britain has an area of 229 850 km<sup>2</sup>.</Paragraph><Paragraph>In scientific notation, 229 850 = 2.2985 × 100 000 = 2.2985 × 10<sup>5</sup>.</Paragraph><Paragraph>  The distance from the Earth to the Sun is 149 600 000 km.</Paragraph><Paragraph>In scientific notation, 149 600 000 = 1.496 × 100 000 000 = 1.496 × 10<sup>8</sup>.</Paragraph><Paragraph>Consider now the bags of rice calculation. 10<sup>15</sup> is 1000 000 000 000 000. So the number of bags of rice is 4503 599 627 000 000. This is a very large number of bags of rice! The king would need to give the woman over four thousand million million bags of rice in week 52. No wonder his accountant was concerned.</Paragraph><Paragraph>As mentioned above, scientific notation is also used for very small numbers. </Paragraph><Paragraph>Try finding <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i323e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i323e.gif" x_folderhash="eb44170e" x_contenthash="59a09126" x_imagesrc="mu120_a_i323e.gif" x_imagewidth="62" x_imageheight="27"/></InlineFigure> on your calculator. </Paragraph><Paragraph/><Paragraph>You should find that the answer on your calculator is 3.125 × 10<sup>−7</sup>. </Paragraph><Paragraph>(This number may be displayed as 3.125 E −7.) This time the index is negative. This is the same as:</Paragraph><Equation id="ueqn049"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u049e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u049e.gif" x_folderhash="eb44170e" x_contenthash="c689bacd" x_imagesrc="mu120_a_u049e.gif" x_imagewidth="303" x_imageheight="31"/></Equation><Paragraph>With practice you may not need the intermediate steps. You may be able to just move the decimal point the appropriate number of places (multiplying by 10<sup>−3</sup> means moving the decimal point 3 places to the left).</Paragraph><Paragraph>  5.2 × 10<sup>−3</sup> = 0.0052</Paragraph><SubSection id="sec003_001_001"><Title>3.1.1 Try some yourself</Title><Activity id="act033"><Heading>Activity 33</Heading><Question><Paragraph> Express each of the following numbers in scientific notation.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) Light travels 9460 700 000 000 km in a year.</Paragraph></ListItem><ListItem><Paragraph>(b) The average distance from the centre of the Earth to the centre of the Moon is 384 400 km.</Paragraph></ListItem><ListItem><Paragraph>(c) Saturn is 1427 000 000 km from the Sun.</Paragraph></ListItem><ListItem><Paragraph>(d) The mass of the Earth is 5976 000 000 000 000 000 000 000 kg.</Paragraph></ListItem><ListItem><Paragraph>(e) The Mediterranean Sea has an area of 2504 000 km<sup>2</sup>.</Paragraph></ListItem><ListItem><Paragraph>(f) Annapurna 1 is 8075 m high.</Paragraph></ListItem><ListItem><Paragraph>(g) The diameter of the Sun is 1392 000 km. Use metres in your answer.</Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) Light travels at 9.4607 × 10<sup>12</sup> km in a year.</Paragraph></ListItem><ListItem><Paragraph>(b) The distance from the centre of the Earth to the centre of the Moon is 3.844 × 10<sup>5</sup> km.</Paragraph></ListItem><ListItem><Paragraph>(c) Saturn is 1.427 × 10<sup>9</sup> km from the Sun.</Paragraph></ListItem><ListItem><Paragraph>(d) The mass of the Earth is 5.976 × 10<sup>24</sup> kg.</Paragraph></ListItem><ListItem><Paragraph>(e) The Mediterranean Sea has an area of 2.504 × 10<sup>6</sup> km<sup>2</sup>.</Paragraph></ListItem><ListItem><Paragraph>(f) Annapurna 1 is 8.075 × 10<sup>3</sup> m high.</Paragraph></ListItem><ListItem><Paragraph>(g) 1392 000 km is 1392 000 000 m (multiplying by 1000). In scientific notation this is</Paragraph></ListItem><ListItem><Paragraph>  1.392 × 10<sup>9</sup> m.</Paragraph></ListItem><ListItem><Paragraph>(Alternatively: 1392 000 km is 1.392 × 10<sup>6</sup> km = 1.392 × 10<sup>6</sup> × 10<sup>3</sup> m = 1.392 × 10<sup>9</sup> m.)</Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act034"><Heading>Activity 34</Heading><Question><Paragraph> The following numbers are given in scientific notation. Write each out as a single decimal number.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) Ben Nevis is 1.343 × 10<sup>3</sup> m high.</Paragraph></ListItem><ListItem><Paragraph>(b) Mercury is 5.8 × 10<sup>7</sup> km from the Sun.</Paragraph></ListItem><ListItem><Paragraph>(c) The distance from the Earth to the nearest star is about 4.3 × 10<sup>13</sup> km.</Paragraph></ListItem><ListItem><Paragraph>(d) The Earth has a circumference of 4.0078 × 10<sup>4</sup> km at the equator.</Paragraph></ListItem><ListItem><Paragraph>(e) The span of the Golden Gate Bridge is 1.28 × 10<sup>3</sup> m.</Paragraph></ListItem><ListItem><Paragraph>(f) The Arctic Ocean has an area of 1.3986 × 10<sup>7</sup> km<sup>2</sup>.</Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) Ben Nevis is 1343 m high.</Paragraph></ListItem><ListItem><Paragraph>(b) Mercury is 58 000 000 km from the Sun.</Paragraph></ListItem><ListItem><Paragraph>(c) The distance from the Earth to the nearest star is about 43 000 000 000 000 km.</Paragraph></ListItem><ListItem><Paragraph>(d) The Earth has a circumference of 40 078 km at the equator.</Paragraph></ListItem><ListItem><Paragraph>(e) The span of the Golden Gate Bridge is 1280 m.</Paragraph></ListItem><ListItem><Paragraph>(f) The Arctic Ocean has an area of 13 986 000 km<sup>2</sup>.</Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act035"><Heading>Activity 35</Heading><Question><Paragraph> Express each of the following in scientific notation.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 0.53</Paragraph></ListItem><ListItem><Paragraph>(b) 0.0075</Paragraph></ListItem><ListItem><Paragraph>(c) 0.000 004</Paragraph></ListItem><ListItem><Paragraph>(d) 0.000 020 01</Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 0.53 = 5.3 × 10<sup>−1</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 0.0075 = 7.5 × 10<sup>−3</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 0.000 004 = 4 × 10<sup>−6</sup></Paragraph></ListItem><ListItem><Paragraph>(d) 0.000 020 01 = 2.001 × 10<sup>−5</sup></Paragraph></ListItem></UnNumberedList></Answer></Activity><Activity id="act036"><Heading>Activity 36</Heading><Question><Paragraph> Express each of the following in conventional decimal notation.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 2.03 × 10<sup>−4</sup></Paragraph></ListItem><ListItem><Paragraph>(b) 1.4 × 10<sup>−3</sup></Paragraph></ListItem><ListItem><Paragraph>(c) 5.67 × 10<sup>−5</sup></Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) 2.03 × 10<sup>−4</sup> = 0.000 203</Paragraph></ListItem><ListItem><Paragraph>(b) 1.4 × 10<sup>−3</sup> = 0.0014</Paragraph></ListItem><ListItem><Paragraph>(c) 5.67 × 10<sup>−5</sup> = 0.000 0567</Paragraph></ListItem></UnNumberedList></Answer></Activity></SubSection></Section><Section id="sec003_002"><Title>3.2 Using scientific notation</Title><Paragraph>Scientific notation can be very useful when estimating the answers to calculations involving very large and/or small decimal numbers.</Paragraph><Example id="exa009"><Heading>Example 9</Heading><Paragraph>A lottery winner won £7851 000. He put the money straight into a deposit account which earns 7.5% interest per annum (i.e. each year). If he wanted to live off this interest, how much per day would it be?</Paragraph><Answer><!--<SubHeading>Solution</SubHeading>--><Paragraph>The amount is £7851 000 × <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i325e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i325e.gif" x_folderhash="eb44170e" x_contenthash="42f4eb77" x_imagesrc="mu120_a_i325e.gif" x_imagewidth="20" x_imageheight="27"/></InlineFigure> ÷ 365.</Paragraph><Paragraph>Estimate first to provide a check for the calculator work.</Paragraph><Paragraph>7851 000 = 7.851 × 10<sup>6</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 8 × 10<sup>6</sup></Paragraph><Paragraph>  <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_i325e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_i325e.gif" x_folderhash="eb44170e" x_contenthash="42f4eb77" x_imagesrc="mu120_a_i325e.gif" x_imagewidth="20" x_imageheight="27"/></InlineFigure> = 7.5 × 10<sup>−2</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 8 × 10<sup>−2</sup></Paragraph><Paragraph>  365 = 3.65 × 10<sup>2</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 4 × 10<sup>2</sup></Paragraph><Paragraph>So the estimate becomes:</Paragraph><Paragraph>  (8 × 10<sup>6</sup>) × (8 × 10<sup>−2</sup>) ÷ (4 × 10<sup>2</sup>).</Paragraph><Paragraph>Now separate the digits from the powers of 10 to give:</Paragraph><Paragraph>  (8 × 8 ÷ 4) × (10<sup>6</sup> × 10<sup>−2</sup> ÷ 10<sup>2</sup>).</Paragraph><Paragraph>Since 8 × 8 ÷ 4 = 16 and 10<sup>6</sup> × 10<sup>−2</sup> ÷ 10<sup>2</sup> = 10<sup>6+<sup>−</sup>2−2</sup> = 10<sup>2</sup>, the estimate is 16 × 10<sup>2</sup> = 1600 (£1600 a day!).</Paragraph><Paragraph>On a calculator, 7851 000 × 0.075 ÷ 365 gives £1613 rounded to the nearest pound, which is quite close to the estimate.</Paragraph></Answer></Example><SubSection id="sec003_002_001"><Title>3.2.1 Try some yourself </Title><Activity id="act037"><Heading>Activity 37</Heading><Question><Paragraph> Use the method outlined in <CrossRef idref="exa009">Example 9</CrossRef> to estimate each of the following, and then use your calculator to evaluate each, giving your answers to six significant figures.</Paragraph><UnNumberedList><ListItem><Paragraph>(a) 2521 ÷ 38</Paragraph></ListItem><ListItem><Paragraph>(b) 17.85 × 286.3</Paragraph></ListItem><ListItem><Paragraph>(c) 1452 ÷ 0.0072</Paragraph></ListItem><ListItem><Paragraph>(d) 0.0053 × 0.0078 ÷ 0.6821</Paragraph></ListItem><ListItem><Paragraph>(e) 0.000 923 × 0.007 67.</Paragraph></ListItem></UnNumberedList></Question><Answer><UnNumberedList><ListItem><Paragraph>(a) Estimate: 2521 = 2.521 × 10<sup>3</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 3 × 10<sup>3</sup></Paragraph><UnNumberedSubsidiaryList><SubListItem><Paragraph>   38 = 3.8 × 10<sup>1</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 4 × 10<sup>1</sup>.</Paragraph></SubListItem><SubListItem><Paragraph>So 2521 ÷ 38 <InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure><InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si149e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si149e.gif" x_folderhash="eb44170e" x_contenthash="934ac64e" x_imagesrc="mu120_a_si149e.gif" x_imagewidth="47" x_imageheight="36"/></InlineFigure> = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si149be.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si149be.gif" x_folderhash="eb44170e" x_contenthash="ac422cfa" x_imagesrc="mu120_a_si149be.gif" x_imagewidth="7" x_imageheight="27"/></InlineFigure> × 10<sup>3−1</sup></Paragraph></SubListItem><SubListItem><Paragraph>= 0.75 × 10<sup>2</sup> = 75.</Paragraph></SubListItem><SubListItem><Paragraph>Calculate: 2521 ÷ 38 = 66.3421 rounded to six significant figures.</Paragraph></SubListItem></UnNumberedSubsidiaryList></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(b) Estimate: 17.85 = 1.785 × 10<sup>1</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 2 × 10<sup>1</sup></Paragraph><UnNumberedSubsidiaryList><SubListItem><Paragraph>  286.3 = 2.863 × 10<sup>2</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 3 × 10<sup>2</sup>.</Paragraph></SubListItem><SubListItem><Paragraph>So 17.85 × 286.3 <InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 2 × 10<sup>1</sup> × 3 × 10<sup>2</sup></Paragraph></SubListItem><SubListItem><Paragraph>= 2 × 3 × 10<sup>1</sup> × 10<sup>2</sup> = 6 × 10<sup>3</sup> = 6000.</Paragraph></SubListItem><SubListItem><Paragraph>Calculate: 17.85 × 286.3 = 5110.46 rounded to six significant figures.</Paragraph></SubListItem></UnNumberedSubsidiaryList></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(c) Estimate: 1452 = 1.452 × 10<sup>3</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 1.4 × 10<sup>3</sup></Paragraph><UnNumberedSubsidiaryList><SubListItem><Paragraph>   0.0072 = 7.2 × 10<sup>-3</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 7 × 10<sup>−3</sup>.</Paragraph></SubListItem><SubListItem><Paragraph>(Notice that in this case it is easier to round to 1.4 than to 1 or 1.5, anticipating the next step, since it is easier to find 1.4 ÷ 7 than 1 ÷ 7 or 1.5 ÷ 7.)</Paragraph></SubListItem><SubListItem><Paragraph>So 1452 ÷ 0.0072 <InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure><InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si150e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si150e.gif" x_folderhash="eb44170e" x_contenthash="f463b499" x_imagesrc="mu120_a_si150e.gif" x_imagewidth="52" x_imageheight="35"/></InlineFigure> = <InlineFigure><Image height="" movedownby="6" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_si150be.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_si150be.gif" x_folderhash="eb44170e" x_contenthash="91b98d0c" x_imagesrc="mu120_a_si150be.gif" x_imagewidth="17" x_imageheight="27"/></InlineFigure> × 10<sup>3–<sup>−</sup>3</sup></Paragraph></SubListItem><SubListItem><Paragraph/></SubListItem><SubListItem><Paragraph>= 0.2 × 10<sup>3+3</sup> = 0.2 × 10<sup>6</sup> = 2 × 10<sup>−1</sup> × 10<sup>6</sup></Paragraph></SubListItem><SubListItem><Paragraph>= 2 × 10<sup>−1+6</sup> = 2 × 10<sup>5</sup> = 200 000.</Paragraph></SubListItem><SubListItem><Paragraph>Calculate: 1452 ÷ 0.0072 = 201 667 rounded to six significant figures.</Paragraph></SubListItem></UnNumberedSubsidiaryList></ListItem><ListItem><Paragraph/></ListItem><ListItem><Paragraph>(d) Estimate: 0.0053 = 5.3 × 10<sup>−3</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 5 × 10<sup>−3</sup></Paragraph><UnNumberedSubsidiaryList><SubListItem><Paragraph>0.0078 = 7.8 × 10<sup>−3</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 8 × 10<sup>−3</sup></Paragraph></SubListItem><SubListItem><Paragraph>0.6821 = 6.821 × 10<sup>−1</sup><InlineFigure><Image height="" movedownby="-2" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/asymptotically.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/asymptotically.gif" x_folderhash="eb44170e" x_contenthash="8ddb333f" x_imagesrc="asymptotically.gif" x_imagewidth="10" x_imageheight="5"/></InlineFigure> 7 × 10<sup>−1</sup>.</Paragraph></SubListItem><SubListItem><Paragraph>So</Paragraph></SubListItem><SubListItem><Equation id="sueqn006"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_su006e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_su006e.gif" x_folderhash="eb44170e" x_contenthash="9aaf69ec" x_imagesrc="mu120_a_su006e.gif" x_imagewidth="316" x_imageheight="158"/></Equation></SubListItem><SubListItem><Paragraph>Calculate: 0.0053 × 0.0078 ÷ 0.6821</Paragraph></SubListItem><SubListItem><Paragraph>= 6.06069 × 10<sup>−5</sup> = 0.000 060 6069 rounded to six significant figures.</Paragraph></SubListItem><SubListItem><Paragraph>(Notice that the calculator gives the answer in scientific notation.)</Paragraph></SubListItem></UnNumberedSubsidiaryList></ListItem><ListItem><Paragraph/></ListItem><ListItem>(e) <Paragraph>0.000 923 × 0.007 67 = 9.23 × 10<sup>−4</sup> × 7.67 × 10<sup>−3</sup></Paragraph><UnNumberedSubsidiaryList><SubListItem><Paragraph>Estimate:</Paragraph></SubListItem><SubListItem><Equation id="ueqn048"><Image height="" src="https://www.open.edu/openlearn/pluginfile.php/93936/mod_oucontent/oucontent/776/mu120_a_u048e.gif" src_uri="https://openuniv.sharepoint.com/sites/informal-lrning/mu120_4m4/10/mu120_a_u048e.gif" x_folderhash="eb44170e" x_contenthash="b67f48ee" x_imagesrc="mu120_a_u048e.gif" x_imagewidth="222" x_imageheight="44"/></Equation></SubListItem><SubListItem><Paragraph>Calculate:</Paragraph></SubListItem><SubListItem><Paragraph>  0.000 923 × 0.007 67 = 7.079 41 × 10<sup>−6</sup>.</Paragraph></SubListItem></UnNumberedSubsidiaryList></ListItem></UnNumberedList></Answer></Activity><Activity id="act038"><Heading>Activity 38</Heading><Question><Paragraph>A light year is the distance light travels through space in one year. The centre of the Milky Way galaxy is 2.6 × 10<sup>4</sup> light years away from Earth. One light year is 9.46 × 10<sup>12</sup> km. How far away is the centre of the Milky Way in kilometers? Estimate your answer first and then use your calculator to do the calculation, giving your answer in scientific notation.</Paragraph></Question><Answer><Paragraph>Estimate: The centre is roughly 3 × 10<sup>4</sup> light years away, and each light year is roughly 9 × 10<sup>12</sup> km, so the distance to the centre is approximately 3 × 10<sup>4</sup> × 9 × 10<sup>12</sup> = 27 × 10<sup>16</sup> = 2.7 × 10<sup>17</sup>.</Paragraph><Paragraph>Calculate:</Paragraph><Paragraph>  2.6 × 10<sup>4</sup> × 9.46 × 10<sup>12</sup> = 2.4596 × 10<sup>17</sup>.</Paragraph></Answer></Activity></SubSection><!--<Box id="box00a">
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