2 The equation of continuity
The conservation of charge is a basic tenet of electromagnetism. It can be simply expressed by the equation
where Qtot is the total charge in the Universe. However, such an equation does not really help us very much, because we are not usually concerned with anything as grand as the whole Universe. Moreover, it leaves out some important physics.
The most interesting aspect of the law of conservation of charge is that it applies locally as well as globally. If an electron were miraculously created here, and a proton were simultaneously, and equally miraculously, created on Mars, the total charge of the Universe would remain constant. But these two miracles would both violate the law of conservation of charge because they do not conserve charge locally, either here or on Mars. Electric charge is conserved in every region of space. We can therefore make a more powerful statement:
The law of conservation of charge
Any variation in the total charge within a closed surface must be due to charges that flow across the surface.
To express this law in mathematical terms, consider a volume V bounded by the closed surface S (Figure 2). Electric current is defined to be the rate of flow of charge across a surface so the law of conservation of charge tells us that
where I is instantaneous current flowing outwards through S into the exterior space and Q is the instantaneous charge in the enclosed volume V. The minus sign arises because a current flowing outwards across the surface produces a loss of charge within the surface.
Now we can express the current I as a surface integral of the current density J:
Using the divergence theorem, we can also write this as
We can express the charge Q as a volume integral of the charge density ρ:
The rate of change of Q within this volume is therefore
Note the use of ordinary differentiation outside the integral and partial differentiation inside the integral. Ordinary differentiation is appropriate outside the integral because Q(t) is a function of time only. By contrast, the charge density depends on spatial coordinates as well as on time. These spatial coordinates remain fixed, so partial differentiation with respect to time is appropriate inside the integral.
Combining Equations 7.1, 7.2 and 7.3 , we conclude that
The fact that this volume integral vanishes for all volumes (no matter how small) implies that the integrand must be equal to zero everywhere, so we have
This is called the equation of continuity. It applies at each point in space and each instant in time and is a direct expression of the local law of conservation of charge. It is a fundamental fact about electromagnetism which applies in all situations and in all frames of reference.
The case of magnetostatics, where all the currents are steady, is of special importance. In this case, we can argue that ∂ρ/∂t must be equal to zero. For, if ∂ρ/∂t were positive at any particular point, it would remain positive there forever, since all the currents are steady. This would lead to an unphysical boundless build-up of charge. A similar argument rules out a negative value of ∂p/∂t. Therefore realistic steady currents are characterised by
However, this is a very special situation. If the currents are not steady, we would expect concentrations of charge to build up in different regions, and then ebb away. In general, ρ varies in time, and div J ≠ 0.
A one-dimensional rod is aligned with the z-axis. At any point along the rod, the current density is given by
where k, ω and A are constants. What can be said about the charge density along the rod? You may assume that the time-average of charge density is zero at each point along the rod.
The current density only has a z-component, so the equation of continuity becomes
Integrating with respect to time, the charge density is
where C(z) is an arbitrary function. In general, it is necessary to allow for such a function, which describes a fixed charge density distributed along the rod. However, C(z) is the time-average of the charge density at position z, which is equal to zero according to information given in the question. Hence,