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White dwarfs and neutron stars
White dwarfs and neutron stars

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3.2 Conditions for degeneracy

Degeneracy can be described in two equivalent ways:

1. The separation between particles is less than their de Broglie wavelength,

multirelation l less than lamda sub dB equals h solidus left parenthesis three times m times k sub cap b times cap t right parenthesis super one solidus two
Equation label: (3)

2. The number of particles per unit volume, n, is greater than the number of available quantum states nQ known as the quantum concentration,

multirelation n greater than n sub cap q equals left parenthesis two times pi times m times k sub cap b times cap t solidus h squared right parenthesis super three solidus two
Equation label: (4)

Before going further, complete the following activity to confirm to yourself that these two conditions are equivalent.

Activity 2

Beginning with the second statement of the condition for degeneracy, n greater than n sub cap q , use the definition of the quantum concentration to derive an expression for the mean separation of the particles, in terms of the de Broglie wavelength. Show that this leads to the first statement for the condition of degeneracy.

Hint: if the mean separation of particles is l , then the number of particles per unit volume is n equals one solidus l cubed .

Comment

The second condition is n greater than n sub cap q , i.e. n greater than left parenthesis two times pi times m times k sub cap b times cap t solidus h squared right parenthesis super three solidus two .

Because n equals one solidus l cubed , substituting gives one solidus l cubed greater than left parenthesis two times pi times m times k sub cap b times cap t solidus h squared right parenthesis super three solidus two .

Taking the (1/3)-power and rearranging the result gives

multiline equation row 1 l less than h solidus left parenthesis two times pi times m times k sub cap b times cap t right parenthesis super one solidus two row 2 Blank less than left parenthesis three solidus two times pi right parenthesis super one solidus two multiplication h solidus left parenthesis three times m times k sub cap b times cap t right parenthesis super one solidus two row 3 Blank less than left parenthesis three solidus two times pi right parenthesis super one solidus two multiplication lamda sub dB row 4 Blank less than 0.7 times lamda sub dB full stop

That is, from the second degeneracy condition, n greater than n sub cap q , we obtain the first degeneracy condition, l less than lamda sub dB .

You have now shown that the two conditions for degeneracy are actually equivalent; they are merely alternative expressions of the same physics. In the following activity, you will see how a third such expression is derived, which is also equivalent.

Activity 3

  • a.Rewrite the second description of degeneracy, n greater than n sub cap q , to find a limit for the thermal energy k sub cap b times cap t . State a third, equivalent condition for degeneracy as a limit on the temperature.

  • b.Calculate values of the quantity h squared times n super two solidus three solidus left parenthesis two times pi times m times k sub cap b right parenthesis in the core of the Sun for (i) protons and (ii) electrons. Assume that the mass fractions of hydrogen and helium are equation sequence part 1 cap x sub cap h equals part 2 cap x sub He equals part 3 0.5 and that the core density of the Sun is rho sub c comma circled dot operator equals 1.48 multiplication 10 super five kg m super negative three . Note that in the solar core, all atoms are fully ionised and that the number density is n equals rho times cap x solidus m for each type of particle.

    The mass of an electron is m sub e equals 9.11 multiplication 10 super negative 31 kg, the mass of a hydrogen nucleus is m sub p equals 1.67 multiplication 10 super negative 27 kg and the mass of a helium nucleus is m sub He equals four times u where u is the atomic mass unit given by u equals 1.66 multiplication 10 super negative 27 kg. As usual Planck’s constant is h equals 6.63 multiplication 10 super 34 cap j s and Boltzmann’s constant is k sub cap b equals 1.38 multiplication 10 super negative 23 cap j cap k super negative one .

  • c.Consider the results to part (b), and state whether (i) protons and (ii) electrons are degenerate in the Sun’s core. Assume that the core temperature of the Sun is cap t sub c comma circled dot operator equals 15.6 multiplication 10 super six cap k .

Answer

  • a.Since n sub cap q equals left parenthesis two times pi times m times k sub cap b times cap t solidus h squared right parenthesis super three solidus two , so the degeneracy condition n greater than n sub cap q implies that n greater than left parenthesis two times pi times m times k sub cap b times cap t solidus h squared right parenthesis super three solidus two .

    Taking the (2/3)-power and multiplying both sides by h squared solidus left parenthesis two times pi times m right parenthesis gives h squared times n super two solidus three solidus left parenthesis two times pi times m right parenthesis greater than k sub cap b times cap t , i.e. k sub cap b times cap t less than h squared times n super two solidus three solidus left parenthesis two times pi times m right parenthesis .

    The third, equivalent condition for degeneracy, in relation to temperature, is: the gas is degenerate if its temperature cap t less than h squared times n super two solidus three solidus left parenthesis two times pi times m times k sub cap b right parenthesis .

  • b.(i) For protons, n sub p equals rho sub c comma circled dot operator times cap x sub cap h solidus m sub p equals 1.48 multiplication 10 super five kg m super negative three multiplication 0.5 solidus 1.67 multiplication 10 super negative 27 kg equals 4.43 multiplication 10 super 31 times m super negative three (i.e. hydrogen nuclei per m3).

    Therefore, for protons, the temperature-related degeneracy condition is

    multiline equation row 1 h squared times n sub p super two solidus three divided by two times pi times m sub p times k sub cap b equals left parenthesis 6.63 multiplication 10 super negative 34 cap j s right parenthesis squared multiplication left parenthesis 4.43 multiplication 10 super 31 times m super negative three right parenthesis super two solidus three divided by left parenthesis two multiplication pi multiplication 1.67 multiplication 10 super negative 27 kg prefix multiplication of 1.38 multiplication 10 super negative 23 cap j cap k super negative one right parenthesis row 2 Blank equals 3.78 multiplication 10 cubed cap j s super two times m super negative two times kg super negative one cap k row 3 Blank almost equals 3800 cap k full stop

    (ii) In the solar core, all atoms are ionised. The electrons are provided by the hydrogen (1 electron per atom) and helium (2 electrons per atom), which each account for 0.5 of the composition by mass. So

    multiline equation row 1 n sub e equation sequence part 1 equals part 2 n sub p plus two times n sub He equals part 3 rho sub c comma circled dot operator times cap x sub cap h divided by m sub p plus two times rho sub c comma circled dot operator times cap x sub He divided by m sub He equals part 4 rho sub c comma circled dot operator times left parenthesis cap x sub cap h divided by m sub p plus two times cap x sub He divided by four times u right parenthesis row 2 Blank equals 1.48 multiplication 10 super five kg m super negative three times left parenthesis 0.5 divided by 1.67 multiplication 10 super negative 27 kg plus two multiplication 0.5 divided by four multiplication 1.66 multiplication 10 super negative 27 kg right parenthesis row 3 Blank equals 6.66 multiplication 10 super 31 times m super negative three full stop

    Therefore, for electrons, the temperature-related degeneracy condition is

    multiline equation row 1 h squared times n sub e super two solidus three divided by two times pi times m sub e times k sub cap b equals left parenthesis 6.63 multiplication 10 super negative 34 cap j s right parenthesis squared multiplication left parenthesis 6.63 multiplication 10 super 31 times m super negative three right parenthesis super two solidus three divided by left parenthesis two multiplication pi multiplication 9.11 multiplication 10 super negative 31 kg prefix multiplication of 1.38 multiplication 10 super negative 23 cap j cap k super negative one right parenthesis row 2 Blank equals 9.12 multiplication 10 super six cap j s super two times m super negative two times kg super negative one cap k row 3 Blank almost equals 9.1 multiplication 10 super six cap k full stop
  • c.The temperature condition for degeneracy is cap t less than n super two solidus three times h squared solidus left parenthesis two times pi times m times k sub cap b right parenthesis . Since cap t sub c comma circled dot operator equals 15.6 multiplication 10 super six cap k , so the temperature in the core of the Sun is (i) much too high for proton degeneracy to have set in, and (ii) marginally too high for electron degeneracy to have set in.

You have seen in the previous activity that a third equivalent expression for the condition of degeneracy can be written as follows:

cap t less than h squared times n super two solidus three solidus left parenthesis two times pi times m times k sub cap b right parenthesis
Equation label: (5)

Sometimes, this third condition is used to describe a degenerate gas as cold, because its temperature falls below some limit. However, this can be misleading because electrons may become degenerate at temperatures of millions of kelvins, which is obviously not cold in the common usage of the word.