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Week 6: Shapes around us

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Week 6: Shapes around us

Introduction

The study of shapes is fundamental to understanding the world that people see around them. Being able to define the properties of both two dimensional shapes, such as triangles, and solid shapes, such as cylinders, enables engineers and designers to build bridges and design new products. Here you’ll begin this area of study by concentrating on basic four-sided shapes, triangles and circles, as well as some solid shapes and how to calculate some of the basic properties of these, such as area and volume.

Maria introduces Week 6 in the video:

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After this week's study, you should be able to:

  • understand some terms used to describe shapes
  • understand the notation used when drawing shapes
  • work out the perimeter and area of simple shapes
  • calculate the volume of simple solids.

1 Geometry

The word geometry comes from two Greek words: ‘geo’ meaning earth and ‘metros’ meaning measurement. So, geometry literally means earth-measurement and in the sense of the earth that is around us, this is what geometry does. It is a branch of maths that, at its basic level, is concerned with describing shapes and space, such as triangles and circles. In order to do this effectively, and to be able to communicate with others exactly what is being measured or described, there is a set of vocabulary and basic definitions that is used to describe angles, lines and shapes. These will be the focus of the first part of this week.

1.1 Angles and lines

Angles measure the amount of turning from one position to another, so for example, you can describe how far around a circle you have moved. Imagine looking straight ahead and then turning around until you return to your starting position. The angle you have turned through is a full turn. If you turn so that you are facing in the opposite direction, you will have made half of a full turn. If you turn from looking straight ahead to facing either directly to your right or directly to your left, you will have made a quarter turn.

A full turn, or a circle, is defined as having 360º (said as 360 degrees). A circle is split into 360 equal parts, each part being 1º. Week 3 of Succeed with maths – Part 1 looks at fractions by using pizzas, and this is very similar. This system was inherited from the Babylonians, whose counting system was based on 60 and who were the first people to use degrees in astronomy.

If one full turn is 360º, this means that a half turn is 180º and a quarter turn is 90º, as shown in Figure 1. This helps us to define some basic ideas in geometry.

The angles in different anti-clockwise turns.
Figure 1 Angles in different anticlockwise turns

Figure 1 helps us to define some of the basic ideas of geometry.

These are:

  • A circle is 360º.
  • A straight line is 180º.
  • A right angle is 90º.

Now, you’ve looked at one common way of measuring the amount of rotation, let’s think briefly about how to describe and show lines precisely.

Figure 1 shows a right angle, which is denoted by a small square drawn at the angle. This tells us that the angle is exactly 90º and not 89º or 91º. When two lines are at right angles to each other, they are also said to be perpendicular.

Lines that will never meet and are always the same distance apart, however far you extend them in either direction are called parallel lines. A railway track is an example of a set of two parallel lines and these are shown on diagrams by using an arrow (or double arrow) drawn on each line, as shown in Figure 2.

Two parallel lines with a single arrowhead in the middle of each line.
Figure 2 Parallel lines

This use of precise language and definitions removes any confusion when you assess angles and lines on a diagram. These also allow us to move onto looking at shapes and the angles and lines that these are constructed from, in the next section.

1.2 Circles and triangles

There are many shapes in everyday life: rectangular windows, triangular roof sections and circular ponds. It is these types of more familiar shapes that will be the focus of this section.

Let’s start with circles, since there is only one type of circle! A circle possesses the property that any point on the circle is always the same distance from the centre point. This distance is known as the radius of the circle. The diameter of a circle is the distance from one edge of the circle to the other, passing through the centre. Finally, the edge of the circle (or the length of this edge) is known as the circumference. You can see all these properties of a circle in Figure 3.

As shown in Figure 3:

A circle with the centre, radius, diameter and circumference labelled.
Figure 3 A circle showing the radius, diameter and circumference

Of course, you also know that a circle has 360º.

Moving on now to think about triangles. These present us with more to consider, as there are several different standard forms that a triangle can take. Some of these, the right-angled triangle, isosceles triangle and equilateral triangle, are shown in Figure 4. Note that sides that are the same length are marked with the same symbol, usually a short line, perpendicular, to the side.

This diagram shows three triangles: Right-angled, isosceles and equilateral.
Figure 4 Right-angled, isosceles and equilateral triangles

A triangle in which all the sides have different lengths is known as a scalene triangle. Some examples are shown below. You will see that a right-angled triangle can also be described as a scalene triangle, as all the sides are different lengths.

Scalene triangles
Figure 5 Scalene triangles

Another important fact is that the angles of a triangle always add up to 180º. To illustrate this, if you cut out any triangle and then tear off the angles, you will be able to arrange them to form a straight line as shown in Figure 6. You might like to try this yourself.

A triangle ABC with its corners and rearranged so that they fit together to make a straight line.
Figure 6 The angles of a triangle add up to 180º

The next section moves to four-sided shapes.

1.3 Four-sided shapes

Shapes that have four straight edges are known collectively as quadrilaterals. The most familiar of these are squares and rectangles. It might seem very obvious how these are defined but a rectangle (it’s not called an oblong in maths!) has four straight sides that are all at right-angles to each other, with opposite pairs of lines being the same length. A square is a special kind of rectangle, where all the sides are the same length. This means that in both shapes, opposite pairs of lines are also parallel. These are both shown in Figure 7 – lines of the same length have been marked with a single or double short perpendicular line.

This shows a rectangle and a square.
Figure 7 A rectangle and a square

What if you have a four-sided shape where only one pair of lines is parallel? This is known as trapezium and an example is shown below in Figure 8. The parallel lines are marked with arrows.

A trapezium, which is a four-sided shape with one set of parallel sides.
Figure 8 A trapezium

If the quadrilateral, a four-sided shape, has two sets of parallel sides, it is called a parallelogram:

A parallelogram, which is a four sided shape with two sets of parallel sides.
Figure 9 A parallelogram

Of course, this definition also means that squares and rectangles are parallelograms!

Now these more familiar shapes have been defined, it is useful to look at how to refer to specific sides or angles in a shape so that these can be clearly communicated to others. This is the subject of the next brief section.

1.4 Describing shapes

When you are describing a geometrical figure or shape, you often need to refer to a particular line or angle on the diagram, so others know what you are referring to. This can be done by labelling the diagram with letters. For example, Figure 10 shows a triangle labelled clockwise at the corners with A,B,C. This is then known as triangle ABC, in which the longest side is AB and the angle cap a times cap c hat times cap b is a right angle. cap a times cap c hat times cap b is the angle formed by the lines AC and CB. The point where two lines meet is known as a vertex (the plural is vertices). So A, B and C are vertices of the triangle.

This is a right-angled triangle.
Figure 10 A triangle labelled ABC

Note that you can use the shorthand notation ‘ prefix white up pointing triangle of cap a times cap b times cap c ’ for ‘the triangle ABC’ if you wish. There is a lot of new maths vocabulary in these last few sections, so you might find it useful to make a note of these to refer back to when completing this next activity, or for this week’s quiz and the badged quiz in Week 8.

Activity 1 What can you see?

Timing: Allow approximately 10 minutes

Look at the image below and then answer the following questions using the letters shown.

The tangram from Section 10.3 but the vertices of the pieces have been labelled.
Figure 11
  • a.Which sets of lines appear to be parellel?
Answer
  • a.

  • b.AB is parallel to DC.

    AD is parallel to GI and BC.

    AI is parallel to EH.

    BD is parallel to HJ

  • b.Which lines are perpendicular?
Answer
  • b.AB is perpendicular to AD and to BC.

    DC is perpendicular to AD and BC.

    EH is perpendicular to DB and HJ.

    AI is perpendicular to HJ and DB.

  • c.How many triangles can you see?
Answer
  • c. prefix white up pointing triangle of cap a times cap b times cap d comma prefix white up pointing triangle of cap d times cap b times cap c comma prefix white up pointing triangle of cap a times cap b times cap f comma prefix white up pointing triangle of cap a times cap d times cap f comma prefix white up pointing triangle of cap d times cap e times cap h comma prefix white up pointing triangle of cap f times cap g times cap i postfix white up pointing triangle and prefix white up pointing triangle of cap h times cap j times cap c full stop
  • d.What other shapes can you see?
Answer
  • d.The parallelogram, GBJI.

    The squares, ABCD and EFIH.

    The trapeziums, DHIF, EHIG, DBJH, BJHE and DGIH.

This completes your work on defining shapes and how to label them in order to describe them clearly to others.

The next section looks at the different ways for measuring shapes.

2 Perimeters

One of the properties of a shape that is measured is its perimeter. This is the distance around the edge of a shape. For a shape with straight edges, you can work out the perimeter by measuring the length of each edge and then adding these together.

For example, one practical application of this would be someone wanting to decorate the room shown in Figure 12, using a border along the top of all the walls. To determine the length of the border they would need to work out the perimeter. So the border would measure:

five m prefix plus of four m prefix plus of five m prefix plus of four m equals 18 m

An alternative way to calculate this would be to note that the pairs of sides are the same length, giving us:

five m prefix multiplication of two plus four m prefix multiplication of two equals 18 m

This shows a rectangle.
Figure 12 What is the perimeter of this rectangle?

Have a go yourself in this next activity.

Activity 2 Around the edge

Timing: Allow approximately 5 minutes
  • a.This figure is formed from three of the shapes. What is its perimeter?
    Figure formed from three of the shapes
    Figure 13 Figure formed from three of the shapes

Answer

  • a.Starting on the left at the top of shape 3 and going clockwise around the figure, the perimeter is:

    five cm prefix plus of 3.5 cm prefix plus of 3.5 cm prefix plus of 3.5 cm prefix plus of five cm prefix plus of five cm prefix plus of 3.5 cm equals 29 cm

    You could have also shown the working as:

    three multiplication five cm prefix plus of four multiplication 3.5 cm equals 29 cm

When a shape has straight sides, you can measure the perimeter fairly easily by considering each side in turn. However, measuring lines that are not straight can be more difficult. If you need the measurement for some practical purpose, then you can use a piece of string to wrap around an object and then measure the string. However, as you’ll discover in the next section there more precise methods to calculate these in maths.

2.1 Perimeters of circles

As you saw earlier in this week, the perimeter of the circle has its own name: the circumference. But is there an easy way to calculate the circumference of a circle as there is with a rectangle?

Let’s investigate this in the following practical activity. For this you will need a tape measure (or a piece of string and a ruler) and five objects such as mugs, cans, bowls or buckets that have a circular top or bottom.

Activity 3 Circles

Timing: Allow approximately 15 minutes

Measure the circumference and diameter of each object in centimetres to the nearest 0.1 cm (or 1 mm). Use the tape measure (or string and ruler) to find the circumference and the ruler to find the diameter.

Write down the diameter and the circumference of each object in a table and calculate the ratio circumference divided by diameter . What do you notice about your answers?

Answer

Here are some results that were obtained when carrying out the activity. The important data to consider are the ratios between the circumferences and the diameters.

Some sample results:

Table 1 Sample measurements of circular-shaped kitchen items
ItemDiameter (in cm)Circumference (in cm) circumference divided by diameter (rounded to 1 decimal place)
Spice jar4.414.13.2
Drinking glass6.620.93.2
Tin container8.6273.1
Mug10.332.33.1
Bowl23.072.83.2

It is difficult to measure these quantities accurately. However, it is noticeable that in each case, the ratio of the circumference to the diameter seems to be about 3.1 or 3.2. In other words, the circumference is just over three times the length of the diameter.

2.2 Using π (pi)

If you could measure these objects more accurately, you would find that the circumference divided by the diameter always gives the same answer. This value is known as ‘pi’ (pronounced ‘pie’) and it is denoted by the Greek letter pi . The value of pi is approximately 3.142, although for most calculations you will be using the pi button on your calculator, which shows pi to many more decimal places.

In fact, pi is an irrational number. This means that it can’t be represented exactly as a fraction and has an infinite number of decimal places, with no repeating pattern of numbers.

This knowledge that the circumference divided by the diameter for any circle gives a constant value of around 3.142 enables a formula to calculate the circumference from the diameter or the radius of a circle to be formed. Therefore:

circumference equals pi multiplication diameter or c equals pi multiplication d

Because the diameter is twice the radius, this can also be written as:

circumference equals pi multiplication diameter or c equals two multiplication pi multiplication r

You will now be asked to select the relevant formula to use in the next activity.

Activity 4 Circumference of a circle

Timing: Allow approximately 5 minutes

Suppose a circular table has a diameter of 1.5 metres. How many people can sit down comfortably for a meal at the table, assuming that each person requires a space of about 0.75 m? Use the button marked with π on your calculator. If you need a hint or tip simply click on ‘reveal comment’.

This is a circle with the diameter marked as 1.5 m.
Figure 14 Diagram of a circular table with a 1.5 m diameter
Comment

If you want some help to visualise the problem you could draw a quick sketch of the table and gaps for each person.

Answer

To see how many people will fit comfortably around the table you need to first work out the circumference of the table.

The diameter is given, so the circumference can be found with the formula:

multiline equation line 1 circumference equals pi multiplication diameter line 2 equation left hand side equals right hand side pi multiplication 1.5 m line 3 equals 4.7 m left parenthesis to one decimal place right parenthesis

Each person needs a space of about 0.75 m in width.

multiline equation line 1 Number of people who can fit around the table equals 4.7 m prefix division of 0.75 m line 2 almost equals six left parenthesis almost equals means approximately equal to right parenthesis

Therefore, six people should be able to fit around the table.

More often than not, the shape of which you need to know the perimeter will not be a simple circle, or rectangle. So, what do you do then? You’ll find out in the next short section.

2.3 Perimeters of mixed shapes

Suppose the shape that you wanted to determine the perimeter of is as shown in Figure 15.

A shape formed of a rectangle and two semicircles.
Figure 15 A shape formed of a rectangle and two semicircles

Start by noticing that the shape is formed of one rectangle and two semicircles. The distance around the two semicircles combined is the same as around a circle with a diameter of 1.6 m. So, calculating the circumference of a circle with this diameter will give us part of the answer. To find the total distance, or perimeter, you then just need to add in the lengths of the longest edges of the rectangle. This gives us the following calculation:

multiline equation line 1 Circumference of circle equals pi multiplication diameter line 2 equation left hand side equals right hand side pi multiplication 1.6 m line 3 equals 5.03 m left parenthesis to two decimal places right parenthesis

multiline equation line 1 Total perimeter equals 5.03 m prefix plus of two multiplication two m line 2 equals 9.03 m left parenthesis to two decimal places right parenthesis

So, if you are faced with a complex shape, look for ways to split these up to help you calculate the perimeter.

Another property of a shape that can be useful to know is the area, or space that it occupies. This is slightly more complicated than the perimeter, but for regular shapes there are a set of formulas to help with this, as you will see in the next section.

3 Areas

If someone is planning to paint a wall, one of the first questions to ask will be how much paint they need. This will obviously depend on the size of the wall and how many coats needed. Fortunately, paint cans usually include information about the area that the paint will cover. For example, on the back of a 2.5-litre can of emulsion paint, it says that the paint will cover ‘up to 35 square metres.’ A square metre is the area that is covered by a square whose sides measure 1 m, as shown in Figure 16. This can also be written as 1 m2. So 35 m2 will be the same area as the area of 35 of these 1-metre squares.

A square with an area of 1 metre squared.
Figure 16 A square with an area of 1 m2

Areas can also be measured in other square units, such as square centimetres (cm2) or square kilometres (km2), depending on what is appropriate to the situation. For example, if you wanted the area of a country, it would not make sense to show this in cm2 or m2 as the value would be very large! Similarly to a square metre, a square centimetre is a square whose sides are 1 cm long, and a square kilometre has sides that are 1 km long. If the diagram below (Figure 17) is drawn on a grid in which the lines are 1 cm apart, then each grid square will have an area of 1 cm2. One way to work out the total area is counting the number of these squares. This gives us 16, so the grid shown is 16 cm2 altogether.

Grid containing different shapes
Figure 17 Grid containing different shapes

You can use the same technique to determine the areas of the shapes shown on the diagram. Try this now in the next activity.

Activity 5 Counting squares

Timing: Allow approximately 5 minutes

All the shapes on the diagram in Figure 17 are made up out of whole squares or half squares. Use this information to work out the areas of each of the shapes.

Answer

The areas in square centimetres are shown in Figure 18:

Grid showing square centimetres
Figure 18 Grid showing square centimetres

Let’s take the top triangle as an example to show how this was worked out.

This triangle is made up of two full squares and four half squares. Four half squares are the same as 2 full squares, so the total area of the top triangle is 4 cm2.

To check the answers, you can add the individual areas and see if they total 16 cm2.

The sum of the individual areas in cm2 = 4 + 4 + 1 + 2 + 1 + 2 + 2 = 16.

This gives confidence in the individual answers and acts as a very useful check.

Counting squares is one way to work out the area of shapes, particularly if they are irregular. However, it is not very convenient in a lot of situations so this is where the power of formulas comes into play once again.

3.1 Formulas for areas

Many areas can be built out of basic shapes such as rectangles, triangles or circles, and these areas can be calculated using formulas. For example, if a rectangular room measures 4 m by 3 m and you are covering it in carpet tiles that are each 1 m square, the tiles can be arranged in three rows, each with four tiles. So the total number of tiles will be 3 x 4 = 12 and the area covered is written as 12 m2.

A rectangle with the length marked as 4 m and the width marked as 3 m.
Figure 19 A rectangle

This area could have been calculated directly, without the need for squares, by multiplying the length of the room by its width. Provided both measurements are in the same units, the following formula holds for any rectangle (including a square):

Area of a rectangle equals length multiplication width

From the formula for the area of a rectangle, the formulas for the area of a parallelogram and a triangle can be derived. Starting with a parallelogram, cut off the left edge and place it next to the right edge to make a rectangle, as in Figure 20. This must have the same area as the parallelogram, as nothing has been added or taken away.

A parallelogram becoming a rectangle
Figure 20 A parallelogram becoming a rectangle

The area of the rectangle can be found by multiplying its length by its height. In the case of a parallelogram, the length is called the base and the width the height. This gives the formula:

Area of a parallelogram equals base multiplication height

Now if this parallelogram is cut in half along a diagonal, this gives two possibilities, as illustrated in Figure 21:

Two parallelograms with the diagonals marked
Figure 21 Two parallelograms with the diagonals marked

In each case, the parallelogram has been split into two triangles that are each half the area of the parallelogram.

This then gives a general formula for the area of a triangle:

Area of a triangle equals one divided by two multiplication base multiplication height

The height goes through the vertex (the point where two lines meet) that is opposite, the base and is always perpendicular, to the base, as shown in Figure 22:

A triangle with the base marked
Figure 22 A triangle with the base marked

You’ll look at an example in the next section before having a go yourself.

3.2 Finding an area using formulas

Figure 23 is a rough sketch of the gable end of a house that needs weatherproofing.

A sketch of the gable end of a house
Figure 23 A sketch of the gable end of a house

To work out the quantity of materials required, the area of the wall is needed. This problem can be broken down by splitting the area into a rectangle and a triangle, then working out these areas and finally adding the two areas together to get the total.

multiline equation line 1 Area of rectanguluar part equals length multiplication width line 2 equals eight m prefix multiplication of six m line 3 equals 48 m super two

The triangle has a base of length 8 m and a perpendicular height of 2 m. So, the area can be calculated as follows:

multiline equation line 1 Area of triangular part equals one divided by two multiplication base multiplication height line 2 equation left hand side equals right hand side one divided by two multiplication eight m prefix multiplication of two m line 3 equals eight m super two

That means the total area of the gable end = 48 m2 + 8 m2.

Now, it’s your turn to put what you’ve learned in this section to use.

Activity 6 Using formulas to calculate areas

Timing: Allow approximately 5 minutes

Figure 24 shows the same diagram as you have already seen in previous activities. This time though, instead of counting the squares to determine the areas, use the relevant formulas from the previous section. Remember that the whole grid measures 4 cm by 4 cm, and each small square is 1 cm by 1 cm.

A picture of the square tangram puzzle.
Figure 24 Grid

Calculate the areas of the following shapes.

  • a.Triangle ADF with AD as the base
Answer
  • a.The base of the triangle is AD. AD = 4 cm.

    The perpendicular height from F onto AD = 2 cm.

    area of a triangle equals one divided by two multiplication base multiplication height

    multiline equation line 1 So the area of triangle ADF equals one divided by two multiplication four cm prefix multiplication of two cm line 2 equals four cm super two

  • b.Parallelogram GBJI with BJ as the base
Answer
  • b.BJ = 2 cm. The perpendicular height from G onto BJ = 1 cm.

    Area of a parallelogram equals base multiplication height

    multiline equation line 1 That means the area of GBJI equals two cm prefix multiplication of one cm line 2 equals two cm super two

Now that you know how to calculate the areas of basic shapes, you can calculate more complicated areas by breaking each shape into basic shapes and adding the individual areas together.

Many area problems can be calculated by using combinations of squares, rectangles and triangles. However, you often need to find circular areas, too. The next section will cover this aspect of areas.

3.3 Areas of circles

You can show that the area of a circle is calculated by multiplying the square of the radius by pi , by splitting the circle into equal sized segments and then arranging these to form a rectangle as shown in Figure 25:

Circle area by sectors
Figure 25 Circle area by sectors

If each segment is made gradually smaller, any ‘bumps’ along the top and bottom edges will be smoothed out to form a line that is closer and closer to being straight. The height of the rectangle will then be the same as the radius of the circle and the length half of the circumference. The area of this rectangle will therefore be equivalent to that of the circle.

The area of a rectangle left parenthesis circle right parenthesis equals radius multiplication one divided by two multiplication circumference

The circumference and radius are related by the following formula:

Circumference equals two multiplication pi multiplication radius

So equation left hand side one divided by two multiplication circumference equals right hand side pi multiplication radius

So putting this together gives:

multiline equation line 1 Area of a circle equals radius multiplication pi multiplication radius line 2 equation left hand side equals right hand side pi multiplication radius squared

The formula for the area of a circle is therefore:

Area of a circle equals pi multiplication radius squared

If you are given the diameter of a circle instead of the radius, the first step to take when working out the area would be to halve the diameter.

See how you get on with applying this new formula in the next activity.

Activity 7 Everyday structures

Timing: Allow approximately 10 minutes

Calculate the areas of the following road and town developments, assuming that the measurements are sufficiently accurate to allow answers to the nearest whole number. Remember to click on ‘reveal comment’ for a hint or tip.

  • a.A roundabout of radius 15.6 m.
Answer
  • a. Area of a circle equals pi multiplication radius squared

    multiline equation line 1 So the area of the roundabout equation left hand side equals right hand side pi postfix multiplication left parenthesis 15.6 m right parenthesis squared line 2 equals 765 m super two

  • b.A circular building with a diameter of 54 metres.
Comment

Remember that you need the radius, not the diameter for the formula for area of a circle.

Answer
  • b.Here you are given the diameter. The radius is half the diameter.

    multiline equation line 1 So radius equals 54 m prefix division of two line 2 equals 27 m

    multiline equation line 1 So comma the area of the circular building equation left hand side equals right hand side pi postfix multiplication left parenthesis 27 m right parenthesis squared line 2 equals 2290 m super two left parenthesis to the nearest whole number right parenthesis

  • c.A semicircular lecture hall with a diameter of 46 m.
Answer
  • c.The area of a semicircle is half the area of a circle.

    So the area of a semicircle equation left hand side equals right hand side one divided by two multiplication pi multiplication radius squared

    The lecture hall has a diameter of 46 m so the radius is 23 m.

    multiline equation line 1 The area of the lecture hall equation left hand side equals right hand side one divided by two multiplication pi postfix multiplication left parenthesis 23 m right parenthesis squared line 2 equals 831 m super two left parenthesis to the nearest whole number right parenthesis full stop

The last few sections have included a number of different formulas, so you might appreciate a quick summary to bring them altogether. You might also like to take a note of them alongside any new vocabulary you’ve come across

  • area of a rectangle equals length multiplication width
  • area of a parallelogram equals base multiplication height
  • area of a triangle equation left hand side equals right hand side one divided by two postfix multiplication base multiplication height
  • area of a circle equation left hand side equals right hand side pi multiplication radius super two full stop

From your study of measurement in Week’s 1 and 2 of the course you will know that there is one final property of shapes that hasn’t been covered, that is capacity or volume. So, you’ll move onto that now in the final part of this week’s study.

4 Volumes

So far you have considered measuring perimeters and areas. But most things in life are not flat; that is, two-dimensional.

Questions like ‘How much does that hold?’ need you to be able to specify the volume of an object. Extending the ideas you learned earlier you can count how many cubes of a certain size will fit into the space. All the sides of a cube are the same length and its six faces are all square.

Useful cubic measurements to use are the cubic millimetre (written as mm3), the cubic centimetre (written as cm3) and the cubic metre (written as m3).

A cube with side lengths of 1 centimetre
Figure 26 A cube with side lengths of 1 centimetre

In each case, the length of the side of the cube is 1 unit. So a cubic centimetre has all its sides of length 1 cm, as shown.

Now imagine filling a cubic centimetre with cubic millimetres. Since there are 10 mm in 1 cm, a cubic centimetre will contain 10 layers with each layer made up of 10 rows, each of 10 cubic millimetres.

This is a 1-centimetre square divided into 100 square millimetres.
Figure 27 A cube of side 1 centimetre with one layer of 100 cubic centimetres shown

So, one times cm super three equals 10 mm prefix multiplication of 10 mm prefix multiplication of 10 mm equals 1000 mm super three

Or a 1 cm by 1 cm by 1 cm cube will hold 1000 cubic millimetres.

Now, suppose you have a box that measures 6 cm by 5 cm by 4 cm. What is its volume? Since all the dimensions are given in centimetres, you can measure the volume in cubic centimetres. Imagine filling the box with 1 cm3 cubes: six rows with five cubes in each row would cover the bottom of the box, and the box would be filled by four of these layers.

A cuboid, also known as a rectangular box.
Figure 28 What is the volume of this box?

So, the total number of cubes used = 6 x 5 x 4 = 120. The volume of the box is therefore 120 cm3. Before you move on to the next section, can you think of a suitable formula for working out the volume of a rectangular box, known as a cuboid?

4.1 Volume formulas

You may have already worked out that the formula for the volume of a cuboid can be calculated using the formula shown below.

Volume of a cuboid equals length multiplication width multiplication height

A cuboid with the length, width and height marked.
Figure 29 A cuboid with the length, width and height marked

Here are the formulas of various other shapes that you may encounter as well. Remember to make a note of them somewhere, as you may need one or another for the quizzes!

Volume of cylinder

Area of base multiplication height equation left hand side equals right hand side pi multiplication radius super two postfix multiplication height

A cylinder with the radius of the base and the height marked.
Figure 30 A cylinder with the radius of the base and the height marked

Volume of a sphere

four divided by three multiplication pi multiplication radius cubed

A sphere with the radius marked.
Figure 31 A sphere with the radius marked

Use the relevant formulas to complete this next activity and apply what you have learned in this section.

Activity 8 A fuel tanker

Timing: Allow approximately 5 minutes
  • a.The container on a fuel tanker is approximately cylindrical, with an internal diameter of about 2.25 m and an internal length of 10 m. Roughly how many cubic metres of fuel will it hold?
Answer
  • a. multiline equation line 1 Volume of a cylinder equals pi multiplication radius squared multiplication height line 2 Radius equals 2.25 m prefix division of two equals 1.125 m

    The length is 10 m, which is in this case equivalent to the height.

    Substituting these values into the formula for the volume of a cylinder:

    multiline equation line 1 Volume of a cylinder equals pi postfix multiplication left parenthesis 1.125 m right parenthesis squared multiplication 10 m line 2 equals 39.76 m super three

    Rounding to the nearest cubic metre, the volume is 40 m3.

  • b.The petrol station has an underground tank that measures 2.5 m by 4 m by 3 m. If the tank is empty, will it hold all the fuel in the tanker?
Answer
  • b.The tank must be a cuboid, as there are 3 dimensions given.

    multiline equation line 1 So the volume of the underground tank equals 2.5 m prefix multiplication of four m prefix multiplication of three m line 2 equals 30 m super three

    Since the fuel tanker will hold about 40 m3 the petrol station’s tank is not large enough to hold all the fuel.

This activity completes your study of shapes this week.

5 This week's quiz

Well done, you've just completed the last of the activities in this week's study before the weekly quiz.

Go to:

Week 6 practice quiz.

Open the quiz in a new tab or window (by holding ctrl [or cmd on a Mac] when you click the link).

6 Summary

This week you may well have encountered some new mathematical language and different ways of drawing shapes to precisely communicate their properties. As well as this new knowledge, there were also quite a few formulas introduced for perimeters, areas and volumes. That’s a lot to take in, so congratulations for working your way through the week!

You should now be able to:

  • understand some terms used to describe shapes
  • understand the notation used when drawing shapes
  • work out the perimeter and area of simple shapes
  • calculate the volume of simple solids.

You can now go to Week 7.

Acknowledgements

This course was written by Hilary Holmes and Maria Townsend.

Except for third party materials and otherwise stated (see FAQs), this content is made available under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 Licence.

Every effort has been made to contact copyright owners. If any have been inadvertently overlooked, the publishers will be pleased to make the necessary arrangements at the first opportunity.

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Week 7.