Skip to content
Skip to main content

About this free course

Download this course

Share this free course

Succeed with maths: part 1
Succeed with maths: part 1

Start this free course now. Just create an account and sign in. Enrol and complete the course for a free statement of participation or digital badge if available.

1.1 The process of adding and subtracting

You might like to watch this next video before attempting Activity 1, which will guide you through the process of adding and subtracting fractions.

Download this video clip.Video player: swm_1_s4_adding_subtracting_fractions.mp4
Copy this transcript to the clipboard
Print this transcript
Show transcript|Hide transcript
 
Interactive feature not available in single page view (see it in standard view).

Activity 1 Adding and subtracting fractions

Timing: Allow approximately 10 minutes

Have a go at these questions, showing your answers in the simplest form or mixed number where relevant. Remember to make sure before you add or subtract to make the denominators the same.

  • a.five divided by 18 plus seven divided by 18

Hint: Are both fractions out of the same number of parts? Remember as always to show your answer in the simplest form.

Answer

Both the given fractions are eighteenths, so they can be added together directly:

equation sequence part 1 five divided by 18 plus seven divided by 18 equals part 2 five plus seven divided by 18 equals part 3 12 divided by 18 equals part 4 two divided by three

To simplify 12 divided by 18 to two divided by three, divide the numerator (top) and the denominator (bottom) by 6.

  • b.three divided by eight plus six divided by eight

Hint: both fractions are eighths, so again you can add them directly.

Answer

The answer is:

equation sequence part 1 three divided by eight plus six divided by eight equals part 2 three plus six divided by eight equals part 3 nine divided by eight

If this is converted to a mixed number, the answer is:

nine divided by eight equals one and one divided by eight
  • c.five divided by six plus three divided by seven

Hint: can you find equivalent fractions for each given fraction that all share the same denominator? What number can be divided by both 6 and 7?

Answer

This sum involves sixths and sevenths, which are different types of fraction. However, you can change both into forty-seconds, since both 6 and 7 evenly divide into 42. So, five divided by six equals 35 divided by 42 by multiplying by 7 and three divided by seven equals 18 divided by 42 by multiplying by 6.

Thus, the sum is equation sequence part 1 five divided by six plus three divided by seven equals part 2 35 divided by 42 plus 18 divided by 42 equals part 3 53 divided by 42 equals part 4 one and 11 divided by 42.

  • d.

Hint: try adding the whole numbers first, and then add the fractional parts together.

Answer

In this calculation you can add the whole numbers first (2 + 3 = 5) and then add the fractions. First, you must convert each fraction into twenty-fourths, as both 3 and 8 divide exactly into 24. So, the sum is: equation sequence part 1 two and two divided by three plus three and one divided by eight equals part 2 sum with 3 summands five plus two divided by three plus one divided by eight equals part 3 sum with 3 summands five plus 16 divided by 24 plus three divided by 24 equals part 4 five and 19 divided by 24

  • e.15 divided by 16 minus five divided by 16

Answer

Both the fractions are sixteenths so you subtract straightaway: equation sequence part 1 15 divided by 16 minus five divided by 16 equals part 2 10 divided by 16 equals part 3 five divided by eight

  • f.19 divided by 24 minus three divided by eight

Hint: first ensure both fractions have the same denominator.

Answer

You need both fractions to be out of the same number of parts (the denominators).

Since eight multiplication three equals 24, you can multiply the top and bottom of three divided by eight by 3 to make the equivalent fraction of nine divided by 24 and then carry out the subtraction.

Therefore: equation sequence part 1 19 divided by 24 minus three divided by eight equals part 2 19 divided by 24 minus nine divided by 24 equals part 3 10 divided by 24 equals part 4 five divided by 12

  • g.Two children were squabbling about chocolate. Josie had been given five divided by 12 of a bar by her aunt and one divided by four of a bar by her dad. Tim had been given one divided by two a bar by his mum and one divided by six by his friend. All the original bars were the same size. Was Josie or Tim given more chocolate, or were they given equal amounts?

Hint: add up what fraction of a bar each child had. To compare your two fractions, cancel each to its lowest terms.

Answer

Josie had five divided by 12 plus one divided by four of a bar. To add these, we need to put them over a common denominator. The common denominator is 12. So five divided by 12 plus one divided by four becomes five divided by 12 plus three divided by 12 equals eight divided by 12. eight divided by 12 cancels down to two divided by three of a bar.

Tim has one divided by two plus one divided by six of a bar. The common denominator is 6. So one divided by two plus one divided by six becomes three divided by six plus one divided by six equals four divided by six. four divided by six cancels down to two divided by three of a bar.

Therefore, Josie and Tim had the same amount of chocolate.

Well done – you’ve completed your first activity involving carrying out calculations with fractions! In the next activity you will look at a more practical application of fractions.