Nested if / if-else statements

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Sometimes we require to execute a set of statements based on the TRUEness or FALSEness of two or more conditions. In such a situation we can use nested if-statement or nested if-else statements.

Syntax- There can be infinite number of syntax for nested if-statement and nested if-else statements.

 

Syntax-1

Syntax-2
if ( condition)
{
             if (condition)
             {
                        Statement(s);
             }
}

if ( condition)
{
             if (condition)
             {
                           if (condition)
                           {
                                         Statement(s);
                            }
             }
}

                  Syntax-3

Syntax-4
if ( condition)
{
             if (condition)
             {
                           if (condition)
                           {
                                  And so on…
                           }
             }
}
 if ( condition)
{
             Statement(s);
}
else
{
                if(condition)
                {
                        Statement(s);
                }
}

 

Syntax-5

Syntax-6
if ( condition)
{
                if(condition)
                {
                        Statement(s);
                }
}
else
{
           Statement(s);
}

 

 if ( condition)
{
                if(condition)
                {
                        Statement-1(s);
                }
                else
                {
                        Statement-2(s);
                }
}
else
{
           Statement-3(s);
}

 

Syntax-7

Syntax-8
if ( condition)
{
                Statement-3(s);
}
else
{
                if(condition)
                {
                        Statement-1(s);
                }
                else
                {
                        Statement-2(s);
                }
}

 

 if ( condition-1)
{
                if(condition-2)
                {
                        Statement-1(s);
                }
                else
                {
                        Statement-2(s);
                }
}
else
{
                if(condition-3)
                {
                        Statement-3(s);
                }
                else
                {
                        Statement-4(s);
                }
}

 

Example-1

Marks of 5 subjects are input through the keyboard. Write a Program in C to print the total marks, percentage and division.


/* Program to display total marks, percentage and division [division.c] */
#include < stdio.h >
#include < conio.h >

void main ( )
{
            // Variable Declaration
            int s1, s2, s3, s4, s5, total ;

            float per ;
            clrscr ( );

            // Input
            printf ( “ \n Enter the marks of Physics \n “ );
            scanf ( “ %d “, &s1 );
            printf ( “ \n Enter the marks of Chemistry \n “ );
            scanf ( “ %d “, &s2 );
            printf ( “ \n Enter the marks of Maths \n “ );
            scanf ( “ %d “, &s3 );
            printf ( “ \n Enter the marks of English \n “ );
            scanf ( “ %d “, &s4 );
            printf ( “ \n Enter the marks of Computer Science \n “ );
            scanf ( “ %d “, &s5 );

            // Processing and Output
            total = s1 + s2 + s3 + s4 +s5 ;
            per = total / 5.0 ;
            printf ( “ \n Total Marks = %d“, total );
            printf ( “ \n Percentage = %f “, per );
            if ( per > = 75 )
            {
                        printf ( “ \n Distinction \n “ );
            }
            if ( per > = 60 )
            {
                        if ( per <  75)
                                    printf ( “ \n First Division \n “ );
            }
            if ( per > = 45 )
            {
                        if ( per <  60)
                                    printf ( “ \n Second Division \n “ );
            }
            if ( per > = 33 )
            {
                        if ( per <  45)
                                    printf ( “ \n Third Division \n “ );
            }
            if ( per < 33 )
            {
                        printf ( “ \n Fail \n “ );
            }
            getch ( );

}


Last modified: Tuesday, 21 September 2021, 9:43 AM