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White dwarfs and neutron stars
White dwarfs and neutron stars

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5 Supernovae

In this section, you’ll see what happens to a star whose final core mass exceeds the Chandrasekhar limit, and subsequently, discover what remnant it may leave behind.

A star with a main-sequence mass greater than or equivalent to 11 times cap m sub circled dot operator will complete all the stages of nuclear fusion that are available. Silicon burning will result in a core composed mainly of iron-56, surrounded by concentric shells of silicon, oxygen, neon, carbon, helium and hydrogen. No energy can be released by the thermonuclear fusion of iron, so the core collapses and the degenerate electrons within it become more and more relativistic. When the mass of the core exceeds the Chandrasekhar limit (about 1.4 times cap m sub circled dot operator ), the degenerate electrons are no longer able to support the core, and a catastrophic collapse follows. The core will essentially collapse on a free-fall timescale, liberating gravitational potential energy.

  • The free-fall timescale is given by tau sub ff equals left parenthesis three times pi solidus left parenthesis 32 times cap g times rho right parenthesis right parenthesis super one solidus two . Calculate the free-fall timescale for a stellar core with a density of rho equals 10 super 14 kg m super negative three .

  • Putting in the numbers to the equation above,

    multirelation tau sub ff equals left parenthesis three multiplication pi divided by 32 multiplication 6.67 multiplication 10 super negative 11 cap n m super two times kg super negative two multiplication 10 super 14 kg m super negative three right parenthesis super one solidus two almost equals 0.007 s full stop
  • The gravitational potential energy released in the collapse of a stellar core of mass M, from an initial radius R1 to a final radius R2, is cap e sub g equals left parenthesis cap g times cap m squared solidus cap r sub two right parenthesis minus left parenthesis cap g times cap m squared solidus cap r sub one right parenthesis . Calculate the gravitational potential energy released when a stellar core of mass 1.4 times cap m sub circled dot operator collapses to a radius of about 10 km.

  • In this case, the final radius is very small, so cap r sub two much less than cap r sub one , and we can neglect the initial gravitational potential energy as it is so small. Therefore the gravitational potential energy released is cap e sub g almost equals cap g times cap m squared solidus cap r sub two . So the energy released by the collapse of a 1.4 times cap m sub circled dot operator stellar core is

    equation sequence part 1 cap e sub g almost equals part 2 6.67 multiplication 10 super negative 11 cap n m super two times kg super negative two multiplication left parenthesis 1.4 multiplication 1.99 multiplication 10 super 30 kg right parenthesis squared divided by 10 super four m almost equals part 3 five multiplication 10 super 46 cap j full stop

As the previous two questions show, the collapse of the core is very rapid and it liberates a vast amount of energy.

The initiation of exothermic (energy-liberating) fusion reactions provides pressure support for stars during their long-lasting burning phases. However, the initiation of endothermic (energy-absorbing) reactions draws kinetic energy out of the material and hence eliminates the pressure support. There are two processes that can absorb energy in the collapsing core: photodisintegration of nuclei by high-energy gamma rays and electron capture processes. In the first, the energy is used to unbind the nuclei, while in the second, energy is converted into the kinetic energy of neutrinos, which stream out of the star largely unhindered. Let’s consider each of these two processes in more detail.