Skip to content
Skip to main content

About this free course

Download this course

Share this free course

Introducing vectors for engineering applications
Introducing vectors for engineering applications

Start this free course now. Just create an account and sign in. Enrol and complete the course for a free statement of participation or digital badge if available.

3.1 Vector addition in component form

Let’s return to Alice and Bob pushing a block of ice, with each pushing on a different face of the block, as illustrated in Figure 22. If Bob applies a force of 130 N to the left face of the block, and Alice applies a force of 110 N to the bottom face, what is the combined force applied to the block?

Described image
Figure 22 Alice and Bob pushing different sides of a block of ice

Figure 23(a) shows an abstraction of the drawing in Figure 22. Here, bold a represents the force applied by Alice, who is below the block, and bold b represents the force applied by Bob, who is to the left of the block.

Described image
Figure 23 Combining the vectors bold a and bold b

Activity 13

Vector bold a is a vertical vector with magnitude 110 N and bold b is a horizontal vector with magnitude 130 N. Write the vectors bold a and bold b in component form.

Vector bold a is a vertical vector so its bold i-component is zero, and bold b is a horizontal vector so its bold j-component is zero. Together, bold a and bold b are the horizontal and vertical components of the resultant vector a plus b, so we can say that

a plus b equals 130 times i plus 110 times j full stop

So the net force on the block of ice in Figure 22 is represented by the vector 130 times i plus 110 times j.

This example was straightforward because we were considering perpendicular forces acting vertically and horizontally. But the process we followed is the same for any vector addition. Using the component form of two vectors bold a and bold b, we add them together algebraically to determine the resultant vector a plus b.

Let’s consider another example. In Figure 24, Alice and Bob are both pushing the same face of the block of ice. If, as before, Bob applies a force of 130 N and Alice a force of 110 N, what is the combined force applied to the block?

Described image
Figure 24 Alice and Bob pushing a block of ice

Again we let the vector bold a represent the force applied by Alice and vector bold b represent the force applied by Bob, so this time bold a and bold b are both horizontal vectors.

Both vectors act horizontally, so are acting in the same direction, the direction of the positive x-axis, and we’d expect them to add up with the net result being a stronger force acting in the same direction. If we add the component forms of bold a and bold b, then this is the result we get:

equation sequence part 1 a plus b equals part 2 130 times i plus 110 times i equals part 3 240 times i full stop

So the resultant vector is 240 times i, and the net effect is a force of 240 N acting in the direction of the positive x-axis. The resultant force on the block of ice is the sum of the forces applied by Alice and Bob, and the block will accelerate faster in the direction they are pushing as we’d intuitively expect.

To summarise, when we add vectors in component form, we add the individual components. This is illustrated visually in Figure 25, where the vector a plus b is the sum of the two vectors bold a and bold b, and the components of a plus b are the sums of the individual components of bold a and bold b. So expressing a plus b in component form gives us the following.

Adding vectors in component form

If bold a equals a sub one times bold i plus a sub two times bold j and bold b equals b sub one times bold i plus b sub two times bold j, then

bold a plus bold b equals left parenthesis a sub one plus b sub one right parenthesis times bold i plus left parenthesis a sub two plus b sub two right parenthesis times bold j full stop
Described image
Figure 25 Sum of the vectors bold a and bold b

For example, the sum of the vectors bold u equals two times bold i plus three times bold j and bold v equals three times bold i minus bold j is given by

equation sequence part 1 bold u plus bold v equals part 2 sum with 3 summands two times bold i plus three times bold j plus three times bold i minus bold j equals part 3 left parenthesis two plus three right parenthesis times bold i plus left parenthesis three plus left parenthesis negative one right parenthesis right parenthesis times bold j equals part 4 five times bold i plus two times bold j full stop

We can also add the vectors using column form. For example:

equation sequence part 1 vector element 1 two element 2 three plus vector element 1 three element 2 negative one equals part 2 vector element 1 two plus three element 2 three plus left parenthesis negative one right parenthesis equals part 3 vector element 1 five element 2 two full stop

Adding column vectors in component form

If a equals vector element 1 a sub one element 2 a sub two and b equals vector element 1 b sub one element 2 b sub two, then a plus b equals vector element 1 a sub one plus b sub one element 2 a sub two plus b sub two.

This method of adding vectors also extends to sums of more than two vectors. For example, if bold a equals four times bold i plus bold j, bold b equals negative three times bold i plus two times bold j and bold c equals two times bold i minus two times bold j, then

bold a plus bold b plus bold c equation sequence part 1 equals part 2 sum with 3 summands left parenthesis four times i plus j right parenthesis plus left parenthesis negative three times i plus two times j right parenthesis plus left parenthesis two times i minus two times j right parenthesis equals part 3 sum with 4 summands four times i minus three times i plus two times i plus j plus two times j minus two times j equals part 4 three times i plus j full stop

Activity 14

Find the following vector sums.

  • a.left parenthesis four times i minus two times j right parenthesis plus left parenthesis negative three times i plus j right parenthesis

  • b.vector element 1 five element 2 three plus vector element 1 negative four element 2 negative three

  • c.sum with 3 summands vector element 1 negative seven element 2 negative four plus vector element 1 two element 2 seven plus vector element 1 five element 2 one

Using component vectors we can add vector quantities algebraically. Let’s reconsider our block of ice example where Alice and Bob are both pulling the block in different directions (see Section 1.2). Using the component form of vectors, we can quickly calculate the combined force applied by Alice and Bob to the block of ice.

Example 3 Calculating the magnitude of combined forces

Alice and Bob have attached ropes to a face of the block of ice and are pulling it in different directions, see Figure 26. Bob pulls with a force of 130 N at an angle of 47° clockwise from the horizontal, and Alice pulls with a force of 110 N at an angle of 24° anticlockwise from the horizontal. Express the forces applied by Alice and Bob in component form, and use these to determine the magnitude of the combined force applied to the block.

Described image
Figure 26 Alice and Bob pulling on a block of ice in different directions

Solution

First let’s express the forces applied by Alice and Bob in component form.

Alice applies a force with magnitude 110 N at an angle of 24°. So in component form we have

equation sequence part 1 a equals part 2 left parenthesis 110 times cosine of 24 super degree right parenthesis times i plus left parenthesis 110 times sine of 24 super degree right parenthesis times j equals part 3 100.49 horizontal ellipsis times i plus 44.74 horizontal ellipsis times j full stop

Bob applies a force with magnitude 130 N at an angle of 360° – 47° = 313°. So in component form we have

equation sequence part 1 b equals part 2 left parenthesis 130 times cosine of 313 super degree right parenthesis times i plus left parenthesis 130 times sine of 313 super degree right parenthesis times j equals part 3 88.65 horizontal ellipsis times i minus 95.07 horizontal ellipsis times j full stop

To calculate the combined force, add the corresponding components:

equation sequence part 1 a plus b equals part 2 left parenthesis 100.49 horizontal ellipsis times i plus 44.74 horizontal ellipsis times j right parenthesis plus left parenthesis 88.65 horizontal ellipsis times i minus 95.07 horizontal ellipsis times j right parenthesis equals part 3 sum with 3 summands 100.49 horizontal ellipsis times i plus 88.65 horizontal ellipsis times i plus 44.74 horizontal ellipsis times j minus 95.07 horizontal ellipsis times j equals part 4 189.14 horizontal ellipsis times i minus 50.33 horizontal ellipsis times j full stop

So the magnitude of the combined force is

equation sequence part 1 absolute value of a plus b equals part 2 Square root of left parenthesis 189.14 horizontal ellipsis right parenthesis squared plus left parenthesis negative 50.33 horizontal ellipsis right parenthesis squared equals part 3 Square root of 38 times 311.24 horizontal ellipsis equals part 4 195.73 times cap n left parenthesis to two d full stop p full stop right parenthesis full stop